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But the RAW data has more highlight (and shadow) information than the in-camera JPEGs, and that's of course what people are refering to when they are talking about "headroom" and "recovery". That's why every DPR (DSLR) review has a section about "RAW headroom", telling us that "..there is typically around 1 EV of extra information available at the highlight end in RAW files..", which enables us to ".. recover detail lost to over-exposure."...Thats a fact and true---> The camera does not recover any highlight details in the raw data.
Same DR as ISO 200, but 1/3 stop less 'headroom' (and 1/3 stop more 'footroom') at ISO 160, right? (And same headroom at ISO 200 and 250?) And btw, I noticed that Andy had a remark in the 100/2.8L IS Macro review about "..the 50D's relatively aggressive optical low-pass filter." (page 3), but isn't your impression the opposite, that the 50D has a relatively weak AA-filter?I just did the math, and it seems 200 and 160 have exactly the same DR, so no change there.Past comments and current impressions are made from past cameras. Based on the numbers I just showed, however, it seems Canon may be clipping more headroom in the 125/250 group than previously (they used the full values up to 16383 before subtracting blackpoint), and now the 160/320 group have more DR (but less headroom) than the "main" ISOs. I gotta go now, I'll look into it more when I get home later.
Yes.Same DR as ISO 200, but 1/3 stop less 'headroom' (and 1/3 stop more 'footroom') at ISO 160, right?I just did the math, and it seems 200 and 160 have exactly the same DR, so no change there.Past comments and current impressions are made from past cameras. Based on the numbers I just showed, however, it seems Canon may be clipping more headroom in the 125/250 group than previously (they used the full values up to 16383 before subtracting blackpoint), and now the 160/320 group have more DR (but less headroom) than the "main" ISOs. I gotta go now, I'll look into it more when I get home later.
Well, I get better pixel-level sharpness with my 50D than my 30D, with a sharp lens. Here's a 100% crop of my 50D with a 90mm Tamron and a 1.4x TC:And btw, I noticed that Andy had a remark in the 100/2.8L IS Macro review about "..the 50D's relatively aggressive optical low-pass filter." (page 3), but isn't your impression the opposite, that the 50D has a relatively weak AA-filter?
I don't have any D3X images suitable for such measurement, but I doubt anyway, that the D3X has any relevance regarding the A900. The sensor may be the same, but the electronics is not. This is not all, but it is enough to dismiss any such claim regarding the A900 based on the D3X.According to DXOmark's DR, the D3X is pretty linear above 400, and 200 has about 1/4 stop more read noise, and 100 about 1/2.
All other things being equal. Adding more bits to an analog to digital conversion process only changes the exactness of the captured data. This does have it's benefits. When you apply a curve translation to the data there is more information to use for more precisely generating the output. This makes it easier to take a part of the input range and expand it's DR in the output. Sure you do loose more information when going from 14 bits to 8 bits than from 12 bits to 8 bits, but you gain in the exactness of hue and saturation able to be transfered from the input to output and that is what counts. That extra exactness of hue and saturation could be used to add more contrast to the clouds and bring out detail in the shadow regions.The pros outwiegh the cons with this form of compession but going from
14 (or more) to 8 bits would have to compromise quality to some degree
giving you less grading latitude.
Most of the measurements on the Sony column ADC sensors (Clark, Martinec, Sheehy, DxO as interpreted by DSPograher) seem to triangulate quite will, with read noises of 6-9 e- at base ISO and 4-5 e- at highest 'real' ISO. Yours might be different, if so you're an outlier, which doesn't necessarily mean you're wrong.I don't have any D3X images suitable for such measurement,According to DXOmark's DR, the D3X is pretty linear above 400, and 200 has about 1/4 stop more read noise, and 100 about 1/2.
Given that the sensor has a digital output, there is no scope for the 'electronics' to be functionally different. What is most likely different is the various signal processing algorithms that Nikon uses and Sony doesn't. The architecture would seem to allow quite a lot of scope for signal processing improvements, either using Nikon special sequencing microcode on the sensor or not,but I doubt anyway, that the D3X has any relevance regarding the A900. The sensor may be the same, but the electronics is not.
Not at all, since the sensor is essentially the same, the D900 forms the baseine for the D3x.This is not all, but it is enough to dismiss any such claim regarding the A900 based on the D3X.
I would be interested in knowing your figures. Emil's measurements on the D300 (which has the same A to D arrangements) put it close at base ISO. I did rather over egg the pudding, saying Canon style cameras had 10x the read noise at base ISO, more like 3-5x, if the various figures are right.When measured on A900 black frames, there is nothing even close to the assessments posted by pixelpeeper.
The pros outwiegh the cons with this form of compession but going from
14 (or more) to 8 bits would have to compromise quality to some degree
giving you less grading latitude.
What you say sounds good in theory, but would really only be applicable if we were talking 8 bits RAW vs 10 bits; the difference between 12, 14, and 16 bits is irrelevant unless manufacturers can stop adding so much noise to the signal, in the ADC and other late-stage parts of the signal chain.All other things being equal. Adding more bits to an analog to digital conversion process only changes the exactness of the captured data. This does have it's benefits. When you apply a curve translation to the data there is more information to use for more precisely generating the output. This makes it easier to take a part of the input range and expand it's DR in the output. Sure you do loose more information when going from 14 bits to 8 bits than from 12 bits to 8 bits, but you gain in the exactness of hue and saturation able to be transfered from the input to output and that is what counts. That extra exactness of hue and saturation could be used to add more contrast to the clouds and bring out detail in the shadow regions.
I don't have any electron counter. If I say measuring , then I mean using the raw data (digital), which is the product of the camera.Most of the measurements on the Sony column ADC sensors (Clark, Martinec, Sheehy, DxO as interpreted by DSPograher) seem to triangulate quite will, with read noises of 6-9 e- at base ISO and 4-5 e- at highest 'real' ISO. Yours might be different, if so you're an outlier, which doesn't necessarily mean you're wrong
1. the D3X has lower noise,Given that the sensor has a digital output, there is no scope for the 'electronics' to be functionally different
Again, I can talk only about the noise measured on the raw data. Let's see same examples, expressed as the standard deviation in percentage of the numerical pixel value range (clipping level minus black level). The standard deviation in absolute values is not useful, because the pixel value range changes with ISO, or in case of Nikons, with bit depth.I would be interested in knowing your figures. Emil's measurements on the D300 (which has the same A to D arrangements) put it close at base ISO. I did rather over egg the pudding, saying Canon style cameras had 10x the read noise at base ISO, more like 3-5x, if the various figures are right.
The sensor is an electron counter. From the raw readings you can derive the values you need. Emil discusses the method on his pages. Essentially, by measuring the shot noise at a given illumination, you can calculate the number of electrons per pixel that that level of illumination represents, since the standard deviation of the shot noise is the square root of the number of electrons. Scaling that to full count gives the saturation count, since sensors a pretty linear. Saturation divided by full count gives the 'gain', The black level count gives the read noise, which can be scaled to electrons using the 'gain'. Nikons are a bit more tricky, since they clip the blacks.I don't have any electron counter. If I say measuring , then I mean using the raw data (digital), which is the product of the camera.Most of the measurements on the Sony column ADC sensors (Clark, Martinec, Sheehy, DxO as interpreted by DSPograher) seem to triangulate quite will, with read noises of 6-9 e- at base ISO and 4-5 e- at highest 'real' ISO. Yours might be different, if so you're an outlier, which doesn't necessarily mean you're wrong
Yes, substantively. The chip give a digital output. There is no scope for different electronics, unless the chip is very different (and there would be no point in it being so similar if it were very different). The signal processing functions may well be very different, but signal processing can equally be applied in the analog domain, using 'different electronics' or in the digital domain, using different digital functions. In electronic design, there has been a steady drift from the analog domain to the digital domain, which has the advantage of being modifiable in firmware. One good indicator that this is happening in the digital domain is that the D3x takes roughly three times the time to create its 14000 levels as does the A900 to create its 3000 levels. I also indicated several ways in which 'different noise' could be produced in the digital domain.In case of Canon (and a few other) cameras I measure the noise on the masked pixels. Neither the D3X nor the A900 pass this info (or there is none on the sensor?), so I can use only black frames. The Canon sensors show, that the black frame measurements are very close to the masked areas.
Should be, if the black frame is black.
1. the D3X has lower noise,Given that the sensor has a digital output, there is no scope for the 'electronics' to be functionally different
2. the D3X can create about 14000 levels (in 14bit mode, roughly), the A900 creates about 3000 levels.
I don't discuss in hardware issues, for I don't know of it at all, but are you saying, that this is the same electronics?
Interesting. They do indeed indicate the flat read noise characteristic of the Sony sensors (since the full count reduces by half with each doubling in ISO) They also show the falling read noise characteristic of the Canon sensors. Scaled to the different full capacity of the pixels, they also triangulate well with the other measurements, so I think yours seem quite consistent to me.However, all that is on the sideline, the topic is read noise.
Again, I can talk only about the noise measured on the raw data. Let's see same examples, expressed as the standard deviation in percentage of the numerical pixel value range (clipping level minus black level). The standard deviation in absolute values is not useful, because the pixel value range changes with ISO, or in case of Nikons, with bit depth.I would be interested in knowing your figures. Emil's measurements on the D300 (which has the same A to D arrangements) put it close at base ISO. I did rather over egg the pudding, saying Canon style cameras had 10x the read noise at base ISO, more like 3-5x, if the various figures are right.
Canon 40D:
ISO 100: 0.039%, ISO 200: 0.044%, ISO 400: 0.060%, ISO 800: 0.1%, ISO 1600: 0.16%
Canon 5D2:
ISO 100: 0.038%, ISO 200: 0.038%, ISO 400: 0.042%, ISO 800: 0.050%, ISO 1600: 0.068%
Nikon D300:
ISO 100: 0.027%, ISO 200: 0.033%, ISO 400: 0.062%, ISO 800: 0.122%, ISO 1600: 0.24%
All the above was measured on the masked areas. The Sony A900 values are from black frames, the green channel:
ISO 100: 0.031%, ISO 200: 0.034%, ISO 400: 0.066%, ISO 800: 0.126%, ISO 1600: 0.24%
I know the method, but I don't accept it. It works only under the assumption, that the read noise is constant (with a given ISO), but it is not.The sensor is an electron counter. From the raw readings you can derive the values you need. Emil discusses the method on his pages
The standard deviation is the noise, and the shot noise part of it changes proportionally to the square root of the change of illumination.since the standard deviation of the shot noise is the square root of the number of electrons
Well, yes, from ISO 400 to 1600, but not from ISO 100 to 400.They do indeed indicate the flat read noise characteristic of the Sony sensors
1. These values can not be and don't need to be scaled. They are the percentage of the noise in the numerical range .Scaled to the different full capacity of the pixels, they also triangulate well with the other measurements, so I think yours seem quite consistent to me.
Here:
Wrong. It works under the assumption that read noise is negligible. The point is to do the white frame test at an illumination much higher than the dark level. If we look at your measurements for the A900, at ISO 100 the read noise is 0.031% of full scale. Full scale is, of course 100%. If we do our light frame test at around 50%, then the shot noise will be 7.071%. If we read both the shot noise and read noise, the combined noise is sqrt(50+0.031^2) = 7.071%. The error in the reading is insignificant, so your mistrust of the method is misplaced.I know the method, but I don't accept it. It works only under the assumption, that the read noise is constant (with a given ISO), but it is not.The sensor is an electron counter. From the raw readings you can derive the values you need. Emil discusses the method on his pages
erm, no, the standard deviation is the standard deviation of the noise,The standard deviation is the noisesince the standard deviation of the shot noise is the square root of the number of electrons
So long as you keep your units of illumination consistent, the standard deviation of the shot noise is the square root of the level of illumination. There is no constant of proportionality involved, whether your units are electrons, ADU or percentage of full scale.and the shot noise part of it changes proportionally to the square root of the change of illumination.
100 is the problem, since 100 is not a 'real ISO', it is just an overexposure of the base ISO. 200 onwards fit on a line.Anyway.
Well, yes, from ISO 400 to 1600, but not from ISO 100 to 400.They do indeed indicate the flat read noise characteristic of the Sony sensors
Anything can be scaled, all scaling does is change the units. Scaling to full capacity places the read noise in 'electrons', since the number of electrons represented by full scale changes with the ISO.1. These values can not be and don't need to be scaled.Scaled to the different full capacity of the pixels, they also triangulate well with the other measurements, so I think yours seem quite consistent to me.
I understand that.They are the percentage of the noise in the numerical range .
Yes, I acknowledged that the 10x was an over statement when it comes to the Canon sensors.2. You wrote in the earlier message The Sony column ADC system seems to have about 50% more read noise at low ISO than at high ISO (which compares with 10x or more in most conventional systems) , and that is, what I had problem with.
You are dealing with different full scales. It is 0.24% of a different total to the 0.031%, therefore the noise percentages are not comparable, but you have scaled (as you said was impossible/unnecessary), but, as I said, 100 is not a 'real ISO', so is not 1600 multiplied by 16.The A900's noise with ISO 1600 is 0.24%, with ISO 100 it is 0.031. 1/16th of the ISO 1600 noise is 0.015%, i.e. the ISO 100 noise is 100% greater, not 50%.
Fine at high ISO, but at low ISO's there is more read noise than there needs to be. If the read noise was the same as it is at high ISO, there would be more DR at high ISO's, nor would there be any need for variable gain amplification, all ISO adjustment could be done by digital scaling.However, that was not my problem. Rather, I don't understand your point. It sounds, like it would be a disadvantage, that the noise at low iso is more, than it is "supposed to be" based on the noise with higher ISO. But why? I see it the other way: the noise with ISO 1600 is "supposed to be" 16 times higher than with ISO 100, but it is only four times higher (40D), only 1.8 times higher (5D2), nine times higher (D300) and 7.7 times higher (A900).
If you want to know what the visible effect of noise is likely to be, it's sensible to reference it to the same units as the image, i.e. photoelectrons (converted photons). ROTFLMAO.Now, we have lots of nice number, but what for? I'm afraid they are good only for discharging the battery of my pocket calculator. LOL
Right in principle, just a little correction on details:Wrong. It works under the assumption that read noise is negligible. The point is to do the white frame test at an illumination much higher than the dark level. If we look at your measurements for the A900, at ISO 100 the read noise is 0.031% of full scale. Full scale is, of course 100%. If we do our light frame test at around 50%, then the shot noise will be 7.071%. If we read both the shot noise and read noise, the combined noise is sqrt(50+0.031^2) = 7.071%. The error in the reading is insignificant, so your mistrust of the method is misplaced.I know the method, but I don't accept it. It works only under the assumption, that the read noise is constant (with a given ISO), but it is not.The sensor is an electron counter. From the raw readings you can derive the values you need. Emil discusses the method on his pages
Not so, for the reason given above. There is a constant of proportionality involved if working in units other than electrons. That is how the gain enters -- it accounts for why the shot noise is not just the sqrt of the RAW level in ADU.So long as you keep your units of illumination consistent, the standard deviation of the shot noise is the square root of the level of illumination. There is no constant of proportionality involved, whether your units are electrons, ADU or percentage of full scale.
Thanks, Emil. You are, of course, right - we are dealing with the statistics of the electrons, not the derived units.Right in principle, just a little correction on details:Wrong. It works under the assumption that read noise is negligible. The point is to do the white frame test at an illumination much higher than the dark level. If we look at your measurements for the A900, at ISO 100 the read noise is 0.031% of full scale. Full scale is, of course 100%. If we do our light frame test at around 50%, then the shot noise will be 7.071%. If we read both the shot noise and read noise, the combined noise is sqrt(50+0.031^2) = 7.071%. The error in the reading is insignificant, so your mistrust of the method is misplaced.I know the method, but I don't accept it. It works only under the assumption, that the read noise is constant (with a given ISO), but it is not.The sensor is an electron counter. From the raw readings you can derive the values you need. Emil discusses the method on his pages
Suppose the pixel holds 40000 electrons at RAW saturation. 50% is 20000 electrons, the read noise is 141 electrons, which is not 7% of 40000 (more like 3.5%). In Poisson statistics the fluctuation is only the square root of the average in the appropriate units, in this case electrons. Read noise .031% of saturation is 12.4 electrons. Total noise at 50% saturation is thus sqrt[141^2+12.4^2]=141.5
Still a negligible correction at the level of accuracy of typical measurements, but just wanted to set the record straight.
Not so, for the reason given above. There is a constant of proportionality involved if working in units other than electrons. That is how the gain enters -- it accounts for why the shot noise is not just the sqrt of the RAW level in ADU.So long as you keep your units of illumination consistent, the standard deviation of the shot noise is the square root of the level of illumination. There is no constant of proportionality involved, whether your units are electrons, ADU or percentage of full scale.
The standard deviation is the standard deviation of whatever you are measuring. As we are talking about digital photography, we can conduct measurements only on the digital image, which consists of pixel values . The noise can be expressed as the standard deviation of those pixel values measured on a totally uniform area, i.e. on which the pixel values would be equal if there were no noise.erm, no, the standard deviation is the standard deviation of the noise,The standard deviation is the noise
Yes, it would work, but the read noise is not negligabe in my books. So, it works if either the full sensel capacity is known (I don't know that), or if the read noise is constant. However, the read noise is not constant based on my measurements + calculations.Wrong. It works under the assumption that read noise is negligible
(taking 3.5% instead of 7%)If we do our light frame test at around 50%, then the shot noise will be 7.071%. If we read both the shot noise and read noise, the combined noise is sqrt(50+0.031^2) = 7.071%. The error in the reading is insignificant, so your mistrust of the method is misplaced
100 is an overexposure of 160. Still it is out of line (the read noise with ISO 200 should be 1.26x that with ISO 160).100 is the problem, since 100 is not a 'real ISO', it is just an overexposure of the base ISO. 200 onwards fit on a line
Hurrrah. I am waiting for the next review posted on this site, stating the noise of the 3D with ISO 6400 is 273.6 photoelectrons .If you want to know what the visible effect of noise is likely to be, it's sensible to reference it to the same units as the image, i.e. photoelectrons (converted photons). ROTFLMAO.
How do you think it varies? You say the read noise is not constant; what observations lead you to that conclusion?Yes, it would work, but the read noise is not negligabe in my books. So, it works if either the full sensel capacity is known (I don't know that), or if the read noise is constant. However, the read noise is not constant based on my measurements + calculations.
I corrected pxlppr's math. 20000 electrons at 50% intensity would lead to 141 electrons of photon noise, or .7%, not 7%. Conversely, .5% noise at 50% intensity means that S/sqrt(taking 3.5% instead of 7%)If we do our light frame test at around 50%, then the shot noise will be 7.071%. If we read both the shot noise and read noise, the combined noise is sqrt(50+0.031^2) = 7.071%. The error in the reading is insignificant, so your mistrust of the method is misplaced
ISO 100 with the A900, 50% intensity, the total measured noise is 0.5% (the read noise at this level is negligable). So much to the usefulness of this calculation.
Emil corrected my mistake - you do need to do the sums in electrons, see his note.(taking 3.5% instead of 7%)If we do our light frame test at around 50%, then the shot noise will be 7.071%. If we read both the shot noise and read noise, the combined noise is sqrt(50+0.031^2) = 7.071%. The error in the reading is insignificant, so your mistrust of the method is misplaced
ISO 100 with the A900, 50% intensity, the total measured noise is 0.5% (the read noise at this level is negligable). So much to the usefulness of this calculation.
Sure, the curve is not absolutely straight. No-one said it was.100 is an overexposure of 160. Still it is out of line (the read noise with ISO 200 should be 1.26x that with ISO 160).100 is the problem, since 100 is not a 'real ISO', it is just an overexposure of the base ISO. 200 onwards fit on a line
It might be more difficult for the uninformed to interpret, but it would provide a consistent metric which could be used reliably to compare between cameras, unlike what they do now.Hurrrah. I am waiting for the next review posted on this site, stating the noise of the 3D with ISO 6400 is 273.6 photoelectrons .If you want to know what the visible effect of noise is likely to be, it's sensible to reference it to the same units as the image, i.e. photoelectrons (converted photons). ROTFLMAO.
I mean, he has have SO much experience
http://forums.dpreview.com/forums/read.asp?forum=1025&message=25379945
almost 2 years of experience since his first studio shot, so he knows about this magical apparatus called "camera"
(FOR THE OP: the 50D has about 2/3 stop more headroom in RAW, but a clear disadvantage on JPEG, about 2 stops, but thats not a sensor issue, its a software problem, easily corrected when converting RAW).
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