An amplifier running with 40dB of negative feedback is linear right up until where it clips. That's the difference between 'transistor sound' and 'tube sound'.
I will have to (and do) take your word on that they are implemented and work that way in practice.
One question: are bandwidth limitations of the amplifier - and thus feedback loop - a problem for linearity of high frequency content in images?
The amplifiers that Bob is talking about relay the image-data from individual photo-sites to an A/D converter. Their own bandwidth limitations would affect all photo-sites in the same way.
In images, "spatial-frequency" relates to "cycles per image dimension" (the height or width of the image-frame, or sometimes a subdivision therein), so it is a different situation than the "cycles per second" (of a sound-pressure-level wave, or of some recorded or electronic signal) of audio-frequency signals. The latter is in the "time domain" (or the "frequency domain", describing time-domain signals), whereas the former is in the "spatial domain" (or the "spatial-frequency domain", describing spatial domain signals).
For example, the pattern of alternating lines and spaces used to test (vertical or horizontal) resolution of imaging systems is a "square wave" (with a 50% duty-cycle) in the spatial-domain. The units of the spatial-domain can be in distance itself (i.e., L/mm "lines per milliMeter", or LP/mm "line-pairs per milliMeter), or expressed with reference to an image-frame itself (i.e., L/H "lines per height", or L/W "lines per width", or LP/H "line-pairs per height", or LP/W "line-pairs per width".
The notations can be confusing. (As I understand it), "LPH" normally implies "lines per height" (and LPW implies "lines per width"), which are actually describing alternating lines and spaces. Thus there are only 1/2 as many actual "line-pairs" as their are (commonly called) "lines". The same is true for "LPM", which signifies "lines" (one-half of a "line-pair") per milliMeter .
One remark: AFAIK CDs are usually mastered at -0.3 to -0.5 dB in order to stay somewhat below the clipping point of DA converters in order to protect from non-linearities (distortion) that happens with many (inexpensive) converter/gain circuits in common CD players.
It is not the Digital to Analog converters that "get it wrong". When the DAC output is "AC-coupled" (using capacitive-coupling, as is pretty much always the case) in an audio signal-path, the square-wave response of a passive (resistor-capacitor) coupling network can (in the worst case) exceed the peak value of the square-wave by a full 6 dB (a linear factor of two). Thus, a full 6 dB of "headroom" would need to be left (relative to the maximum signal level that can be reproduced by any amplifier in the subsequent signal-path). As you know, such is rarely the case.
Frankly I never cared how these things are implemented on their lowest level, but now I wonder (and should maybe ask my contacts at RME Audio) how amplifier circuits inside and around are build up (closed vs. open loop). But that's pure curiosity and really not the topic of this thread.
Closed loop negative-feedback amplifiers have been widely used since the era of vacuum tube amplifiers. Transistors and FETs and operational amplifiers made up of such discrete semiconductors are capable of providing much higher open-loop voltage/current gains than vacuum tube configurations. When a feedback-loop is closed around that high-gain amplification, the net result is a much higher "loop-gain" (which is the "margin" of extra gain left after the open-loop-gain is divided by the closed-loop-gain).
When calculating the above types of "gains" using (logarithmic) deciBels, the calculations become sums and differences (which represent linear multiplications and divisions). That is the more common way that such things are described. 6 dB is (very close to) a linear factor of two, and is also the same as the weighting of a digital binary (M.S. Digit) "bit" in the value of a binary number.