P
Peter Mathews
Guest
Yes, theoretically, in a perfect system, the size of the pixels wouldn't matter as long as they covered the same surface area however, there are losses due to physical problems. The space in between the pixels for example. The space between can't gather photons so there is a loss if you use 4 pixels instead of one for any given area. It may be small but, it's there. Also, larger pixels can be made more efficient (conductor dimensions and amplifier efficiency just to name a couple). There is also the amplification factor. 1/4 the size means twice the gain. More gain equals more noise.Peter,The larger pixels of a lower resolution sensor have less noise (the first place) therefore require less NR. What's the point of higher resolution if the individual pixel signals are so noisy you have to apply aggressive NR to get rid of it thus, smudging detail.
Why do you think that the noise of an image is proportional to the noise of its individual pixels?
If you had two cameras with sensors that measured 3mm x 2mm, neither camera added any noise, and one of the cameras had 6 pixels and the other had 24 pixels, what would be the ratio of the SNR of a pixel on the 6 pixel sensor to that of a pixel on the 24MP sensor at the same exposure? What would be the ratio of the SNR of the image from the 6 pixel sensor to the SNR of the image of the 24MP sensor.
If the theory that more pixels for any given surface area is more critical than actual pixel dimensions than the 48MP A7R-II should literally blow the A7S-II out of the water in image quality at higher ISO's but it doesn't. At best, it comes close but empirical evidence (forget DxoMark rubbish) suggests that lower resolution sensors at current technology levels still hold the upper hand. Why else would Sony make the A7S-II still?
Studio comparison scenes where a smaller resolution image is upscaled (or cropped) to match the higher resolution image are obfuscations because cropping is akin to a signal amplification so if the A7S-II image cropped to match the A7R-II image shows the exact same noise, you have to conclude the inherent SNR in the A7R-II image is greater than the A7S-II image by whatever the crop factor used to get the images displayed to the same size. So, if we take a picture of a sphere at 50 meters with both cameras and enlarge the image from the 12MP sensor so that the size of the sphere matches the image from the 48MP sensor and the noise is the same, the larger sensor image has to have a greater SNR!
This is from Cambridgeincoulour.com-
"Does all this mean it is bad to squeeze more pixels into the same sensor area? This will usually produce more noise, but only when viewed at 100% on your computer monitor. In an actual print, the higher megapixel model's noise will be much more finely spaced — even though it appears noisier on screen (see "Image Noise: Frequency and Magnitude"). This advantage usually offsets any increase in noise when going to a larger megapixel model (with a few exceptions)."
So, the small pixel, higher resolution sensor "seems" to have the same SNR in actual print. It's when you start cropping it becomes clear it's not.
That's my whole point. If you get the same "perceived" SNR from a 48MP sensor camera than from a 12MP camera? Why spend more money on the more expensive sensor? Any advantage in resolution is lost due to the need to reduce the greater noise, even at base ISO.
I was teetering on getting the D810 vs. my D750 now I'm glad I didn't.

