Surface Area (SA) of the rectangle is (a x b).... therefore
SA of 23mm x 15.5mm sensor is 356.5mm square (APS)
SA of 36mm x 24mm sensor is 864mm square (FF)
to find out how much bigger (in %) the area of FF sensor is in
comparison to APS sized sensor we assume the APS size sensor to be
100%. So the difference between the % of the FF sensor (in APS
units) and APS size sensor is the additional surface area.
% of FF sensor = (864 x 100)
356.5
Which gives us 245.69%.
So this result shows us that we can fit a suface area of 2.5 APS
sized sensors in the suface ares of a FF sensor.
The difference in % between the two sensors is: 245.69-100=145.69%
so both of you are wrong; the actual differense in surface area
between FF sensor and APS sized sensor if 145.69%
Igor
increase 50% = x 1.5 (that looks like our crop factor)
increase 125% = x 2.25
Increase the S2 sensor by 50% = 34.5mm x 23.25mm
Increase the S2 sensor by 125% = 51.75mm x 34.875mm
We can prove it another way....
Take 50% of each side of the S2 sensor then add to side...
50% of 23mm = 11.5mm + 23mm = 34.5mm
50% of 15.5mm = 7.75mm + 15.5mm = 23.25mm
Take 125% of each side of the S2 sensor then add that to each side...
125% of 23mm = 28.75mm + 23mm = 51.75mm
125% of 15.5mm = 19.375mm + 15.5mm = 34.875mm
50% is much closer to full frame than 125%.
So to clearify: it is 100% more pixels in 50% of the space. That
is of course going on the previous stated rumor of 12mp at full
frame.
-James
Bernie,
Remember that the S2 has 6 million sensors natively. So to get 12
million sensors in a FF chip, they would have to fit 6 million more
sensors in 50% (difference between FF and current sensor) of the
space. Something has got to give and it usually means the pixels
will get smaller.
-James
They will need compicated algorithms then to guess what was in between the pixels. This will be Bayer Pattern II...
