24-70 f4 vs apsc f2.8 lenses?



I will leave you with these two examples . Both images are shot with a similar framing . Both are shot at the same nominal aperture, both are shot at the same shutter speed of the same subject in the same light at the same ISO . Going by your suggestion tell me do you think they are "exposed" the same ?

b209ff218a914e988d1df4bce39c36d9.jpg
I don't know what "nominal" aperture means.

If the two images were shot at the same aperture (f-stop), shutter speed (and iso depending on what you mean by exposure), then yes, they were exposed the same. Are we arguing over the definition of exposure?
 
I think the only people who would argue that would be people who don't know how to read.

beatboxa wrote:

A 24-70mm F/4 on a full frame camera is essentially equivalent to a 16-47mm F/2.8 on APS-C in terms of everything. Including DoF, light captured, and shot noise.
Not everything. The exposure is not the same.
The misunderstandings of equivalence baffle me read through DPreviews take on it in the link below. Or for a deeper more comprehensive explanation look at the second link

https://www.dpreview.com/articles/2666934640/what-is-equivalence-and-why-should-i-care

http://www.josephjamesphotography.com/equivalence/

Ignoring how folk mislabel exposure that is a whole other kettle of fish :-) . The bottom line from a photographic perspective is. If you take an image on APS with a 16mm lens at F/2.8 and one on FF with a 24mm.

The resulting image { minor modern sensor differences notwithstanding } . You will have two images with the same diagonal AOV, the same DOF and same total light thus same noise { assuming you increase the ISO to match the shutter speed }. So as far as it goes you will indeed have two equivalent images .
The 16mm on APS-C would need to be f2 to have the same minimum DOF as the 24mm f2.8 goes on FF. Or, if the 16mm APS-C lens is f2.8, then the 24mm FF lens woukd need to be f4.
So it is perfectly reasonably to say that an F/2.8 lens on APS will do the same job as an F/4 lens on FF

--
Jim Stirling:
It is not reason which is the guide of life, but custom. David Hume
--
Lance B
https://www.flickr.com/photos/35949907@N02/?
http://www.pbase.com/lance_b
 
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I think the only people who would argue that would be people who don't know how to read.

beatboxa wrote:

A 24-70mm F/4 on a full frame camera is essentially equivalent to a 16-47mm F/2.8 on APS-C in terms of everything. Including DoF, light captured, and shot noise.
Not everything. The exposure is not the same.
The misunderstandings of equivalence baffle me read through DPreviews take on it in the link below. Or for a deeper more comprehensive explanation look at the second link

https://www.dpreview.com/articles/2666934640/what-is-equivalence-and-why-should-i-care

http://www.josephjamesphotography.com/equivalence/

Ignoring how folk mislabel exposure that is a whole other kettle of fish :-) . The bottom line from a photographic perspective is. If you take an image on APS with a 16mm lens at F/2.8 and one on FF with a 24mm.

The resulting image { minor modern sensor differences notwithstanding } . You will have two images with the same diagonal AOV, the same DOF and same total light thus same noise { assuming you increase the ISO to match the shutter speed }. So as far as it goes you will indeed have two equivalent images .
The 16mm on APS-C would need to be f2 to have the same minimum DOF as the 24mm f2.8 goes on FF. Or, if the 16mm APS-C lens is f2.8, then the 24mm FF lens woukd need to be f4.
We were taking about the 24-70mm F/4 :-) As my concluding point below suggests
So it is perfectly reasonably to say that an F/2.8 lens on APS will do the same job as an F/4 lens on FF
 
I think the only people who would argue that would be people who don't know how to read.

beatboxa wrote:

A 24-70mm F/4 on a full frame camera is essentially equivalent to a 16-47mm F/2.8 on APS-C in terms of everything. Including DoF, light captured, and shot noise.
Not everything. The exposure is not the same.
The misunderstandings of equivalence baffle me read through DPreviews take on it in the link below. Or for a deeper more comprehensive explanation look at the second link

https://www.dpreview.com/articles/2666934640/what-is-equivalence-and-why-should-i-care

http://www.josephjamesphotography.com/equivalence/

Ignoring how folk mislabel exposure that is a whole other kettle of fish :-) . The bottom line from a photographic perspective is. If you take an image on APS with a 16mm lens at F/2.8 and one on FF with a 24mm.

The resulting image { minor modern sensor differences notwithstanding } . You will have two images with the same diagonal AOV, the same DOF and same total light thus same noise { assuming you increase the ISO to match the shutter speed }. So as far as it goes you will indeed have two equivalent images .
The 16mm on APS-C would need to be f2 to have the same minimum DOF as the 24mm f2.8 goes on FF. Or, if the 16mm APS-C lens is f2.8, then the 24mm FF lens woukd need to be f4.
We were taking about the 24-70mm F/4 :-) As my concluding point below suggests
The statement in your original post above was ambiguous and simply stated that "If you take an image on APS with a 16mm lens at F/2.8 and one on FF with a 24mm" it would have the same AOV and DOF. That reads to me that they you are saying both are f2.8.
So it is perfectly reasonably to say that an F/2.8 lens on APS will do the same job as an F/4 lens on FF
 
I think the only people who would argue that would be people who don't know how to read.

beatboxa wrote:

A 24-70mm F/4 on a full frame camera is essentially equivalent to a 16-47mm F/2.8 on APS-C in terms of everything. Including DoF, light captured, and shot noise.
Not everything. The exposure is not the same.
The misunderstandings of equivalence baffle me read through DPreviews take on it in the link below. Or for a deeper more comprehensive explanation look at the second link

https://www.dpreview.com/articles/2666934640/what-is-equivalence-and-why-should-i-care

http://www.josephjamesphotography.com/equivalence/

Ignoring how folk mislabel exposure that is a whole other kettle of fish :-) . The bottom line from a photographic perspective is. If you take an image on APS with a 16mm lens at F/2.8 and one on FF with a 24mm . The resulting image { minor modern sensor differences notwithstanding } . You will have two images with the same diagonal AOV, the same DOF and same total light thus same noise { assuming you increase the ISO to match the shutter speed }. So as far as it goes you will indeed have two equivalent images . So it is perfectly reasonably to say that an F/2.8 lens on APS will do the same job as an F/4 lens on FF
Question: I have an APS-C sensor camera and a FX sensor camera. With each I shoot the same grey card at 1/100s, f/2.8, iso 100. Are the two exposed the same or not?

Related question, when you go to the camera store and ask to buy a light meter, do they ask what size sensor you will be metering?

It baffles me how much resistance there is to agreeing that exposure is not dependent on sensor size.
Where does he argue that exposure will be dependent on sensor size? Pls give a quote. As far as I see nobody is arguing with that. Exposure and total light are different.

Here`s wiki

https://en.wikipedia.org/wiki/Exposure_(photography)

"In photography, exposure is the amount of light per unit area"

Look at those. Is exposure the same? Obviously, no. Are they equivalent images (except for small WB and FOV mismatch)? Yes, they are.

aacdf4ae79904e73b0ad9900f7d0d8d1.jpg
 
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Yes, except that due to optics the rendering will be somewhat different. It is like when we crop a image, the equivalence is never perfect.

A dx lens which is as big as a FF can be made edge to edge sharpe, while for the full frame that dimension might not be enough,
 
A 24-70mm F/4 on a full frame camera is essentially equivalent to a 16-47mm F/2.8 on APS-C in terms of everything. Including DoF, light captured, and shot noise.
Let's compare 24 mm f4 on FF vs. 16 f2.8 on Dx, assuming same shutter speed and same sensor technology (like shooting with an FF camera either in FF mode or using its Dx crop mode). Here is how I understand what you are trying to say:
  • Angle of view are the same (obviously)
  • DOF is the same
  • The lens at F2.8 will transmit twice as much photons as the lens at F4, regardless of the format used
  • That light is projected over a surface which is a little more than twice as large on the FF camera (we'll call it 2 fold larger to simplify)
  • Therefore the overall number of photons captured by the sensors will be the same, because the collection of photons over a surface which is about twice as large cancels out the difference in apertures.
Is this what your reasoning is?
To avoid confusion, I think it's important to separate inputs & outputs and to introduce focal lengths.

In terms of equivalent outputs, here is what I am saying:
  • Angle of view are the same
  • DoF is the same
  • Noise is the same
  • Dynamic range will be the same (until reaching the lowest base ISO (100) of the larger sensor, which is outside of the possible range of the smaller sensor. But for all others, it will be the same.
  • The end result pictures will look the same
There are tiny, immaterial nuances such as diffraction limits, but that's the general rule.

But each will take a different path to get there. Below is that path, and diagrams to illustrate. Let's start with the light path:

d334e0ddd692449ea9513bb69bc0817c.jpg.png

There are many steps, with multiple enlargements, digital processings, etc.
  • First, the subject, lighting, distance, etc. is the same. The subject is just sitting there reflecting scattered photons in all directions.
  • In step 3, some of these photons must be caught by a "glass net"--this is the entrance pupil of the lens. The larger the entrance pupil ("aperture") is, the more photons one can catch. A 24mm F/4 lens and a 16mm F/2.8 lens have the same aperture, regardless of format. Each has a 6mm diameter, and a 28.3mm² surface area (round).
Let's visualize this again for emphasis. Here are what a lens' specs mean:

e17eaa187c9946958afc812a60534dd7.jpg.png

And here they are compared for a 24mm F/2.8, a 24mm F/4, and a 16mm F/2.8:

ce4017117d5b42008abe60705d2d82ad.jpg.png

Step 3 (the aperture) is where you are catching all of your light. Also where almost all of the shot noise comes from. Because if photons only sparingly get captured in the first place, you'll have noise. The electronic noise from the sensor is so tiny today it's almost non-existent, and it happens further down the stream.

All of the other steps are just how you record & store what you caught. Note that 24mm F/4 & 16mm F/2.8 capture the same light, but just refract it differently. 24mm F/2.8 actually captures more light. Let's say 24mm F/4 and 16mm F/2.8 at a given shutter speed allow you to capture 100 photons. 24mm F/2.8 would capture 200--and it does so from even more oblique angles of incidence (which is why aperture & distance also determine DoF, but that's another story).

And step 4--the movie projector step--is very important too.

8d53215ac3ea4ac1a4b121317a2d02e0.jpg.png

The movie projectors by this point are projecting the same light: both have 6mm apertures (24mm F/4 or 16mm F/2.8). They basically have the same light bulbs inside them, and the same image.

You can change the intensity of light by moving a projector further from the screen (making it dimmer), but you never actually change the quality or amount of light. This is changing the focal length. The screen on the tail end is like the sensor size, and the combination provides the angle of view.

So if you were projecting 100 photons, they're either going to be spread across a smaller 1mm² area (meaning 100 photons per mm²) or a larger 2mm² area (meaning 50 photons per mm²) or anything else. But your camera still counts 100 photons regardless of format.

And then finally, the ISO--and digital processing in general--is also a source of confusion. The ISO just digitally brightens the light you already captured. If you capture the same amount of light (input), and you have the same final projection (output), you will apply the same brightening. The ISO is different because of where this happens--it's only the first half. But on the tail end, you also have to enlarge the image. Digitally enlarging an ISO 3200 from an APS-C means enlarging it twice as much as ISO 6400 from a full-frame. So these effects offset each other, and you end up with the same image.

This, btw, is also why you'll see dynamic ranges and ISOs scale 1 stop between these formats. Because the measurements assume the same sized output & viewing conditions. For example, on bclaff's photonstophotos.net site, you'll see this blurb :
  • The Photographic Dynamic Range Axis
    Recall that this value is normalized for the Circle Of Confusion (COC) that is appropriate for the sensor size. PDR is the dynamic range you would expect in an 8x10" print viewed at a distance of about arms length.
And when you compare an APS-C sensor to a similar generation full-frame at the same ISO, its PDR is roughly 1 stop behind. Eg. A Z50 at ISO 3200 has a PDR of 6.1, while a Z6 at ISO 3200 has a PDR of 7.19 (and at 6400, it is 6.18). 6.1 and 6.19 are essentially the same--they are a tiny fraction of a stop.

So now, the two equivalent paths are:

60a3c7c23ae047a68b2f4d3c233ba7f5.jpg.png

Note: equivalent, not equal. Same input scene. Same output photograph. Different paths to get there.

So at the end of the day:
  • Both a 24mm F/4 and a 16mm F/2.8 lens have the same apertures, and different f-numbers.
  • A 24mm F/4 on full frame and a 16mm F/2.8 on APS-C will capture the same amount of light (noise), from the same surface area (DoF), and same angles of view
  • The FF in the above scenario will have a recorded ISO of twice higher, but the light captured will be the same
  • When viewed at the same size, the APS-C will need to be scaled twice as much, resulting the same output
And again, I will include an even more extreme example. This is a micro four thirds vs full frame, from the same distance, with the same shutter speed (1/40). Micro four thirds is a 2x crop factor, which is twice the difference between full-frame & APS-C.

Micro four thirds:
  • 20mm focal length
  • F/2 (=10mm aperture)
  • ISO 1600
Full-frame:
  • 40mm focal length
  • F/4 (=10mm aperture)
  • ISO 6400
e5f0e533edeb4be485111289215eedc9.jpg

c6caf2bbd27d43beba0fdfc47a1c0ac0.jpg

Equivalence means you ended up with the same picture, regardless of the path you took.

Equivalent settings are easy to determine for given shooting conditions:
  • Same shutter speed
  • ISO is twice as much on FF than APS-C
  • F-number is 1 stop slower on FF than APS-C
  • Focal length is 1.5x longer on FF than APS-C
 
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for now I will have to do with the 24-70 f4

I understand that f4 lens in FF is equivalent to f2. 8 apsc in terms of bokeh but what about light?

Fuji camera ISO are a bit darker than Nikon ones, meaning Iso 3200 with fuji = iso 2500 with the Z6.
Your gear list includes 2 Nikon bodies - the Z6 and 7 - I presume you refer to the 24-70 f4 S.

f4 light level is f4 light level - meaning either system should provide the same exposure with the same scene and light level.

Different cameras use different exposure systems. There can be modest variations because of this - but large exposure differences require investigation.

As a guide - for the same angle of view which means are zooming out or moving further back with a crop sensor - involves a depth of field difference of about 1 crop between Nikon FX and DX.

--
Leonard Shepherd
In lots of ways good photography is much more about how equipment is used rather than anything else.
 
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I think the only people who would argue that would be people who don't know how to read.

beatboxa wrote:

A 24-70mm F/4 on a full frame camera is essentially equivalent to a 16-47mm F/2.8 on APS-C in terms of everything. Including DoF, light captured, and shot noise.
Not everything. The exposure is not the same.
The misunderstandings of equivalence baffle me read through DPreviews take on it in the link below. Or for a deeper more comprehensive explanation look at the second link

https://www.dpreview.com/articles/2666934640/what-is-equivalence-and-why-should-i-care

http://www.josephjamesphotography.com/equivalence/

Ignoring how folk mislabel exposure that is a whole other kettle of fish :-) . The bottom line from a photographic perspective is. If you take an image on APS with a 16mm lens at F/2.8 and one on FF with a 24mm.

The resulting image { minor modern sensor differences notwithstanding } . You will have two images with the same diagonal AOV, the same DOF and same total light thus same noise { assuming you increase the ISO to match the shutter speed }. So as far as it goes you will indeed have two equivalent images .
The 16mm on APS-C would need to be f2 to have the same minimum DOF as the 24mm f2.8 goes on FF. Or, if the 16mm APS-C lens is f2.8, then the 24mm FF lens woukd need to be f4.
We were taking about the 24-70mm F/4 :-) As my concluding point below suggests
The statement in your original post above was ambiguous and simply stated that "If you take an image on APS with a 16mm lens at F/2.8 and one on FF with a 24mm" it would have the same AOV and DOF. That reads to me that they you are saying both are f2.8.
So it is perfectly reasonably to say that an F/2.8 lens on APS will do the same job as an F/4 lens on FF
The line at the end of my post which I highlighted for you and is right above this reply . Makes it abundantly clear that I was continuing the discussion about the 24-70mm F/4 . In case this line doesn't make it clear I will reiterate for the sake of pedantry that "it is perfectly reasonably to say that an F/2.8 lens on APS will do the same job as an F/4 lens on FF" :-) You did I presume read the title and content of the OP ? The original title was kept in every post I made and replied to namely "24-70 f4 vs apsc f2.8 lenses"
 
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Where does he argue that exposure will be dependent on sensor size? Pls give a quote. As far as I see nobody is arguing with that. Exposure and total light are different.
From the start, all I have been saying is that the same scene, shot once on a FF sensor at f/2.8, 1/100s and then again on a cropped sensor at f/2.8, 1/100s are exposed the same. If both are shot at the same iso, they will also be equally bright. Whereas, the exposure is not the same if the ff sensor body aperture is set to f/4.

This shouldn't be controversial. It's one of the most fundamental principles of photography. I honestly don't understand all the pushback.
 
Where does he argue that exposure will be dependent on sensor size? Pls give a quote. As far as I see nobody is arguing with that. Exposure and total light are different.
From the start, all I have been saying is that the same scene, shot once on a FF sensor at f/2.8, 1/100s and then again on a cropped sensor at f/2.8, 1/100s are exposed the same. If both are shot at the same iso, they will also be equally bright. Whereas, the exposure is not the same if the ff sensor body aperture is set to f/4.

This shouldn't be controversial. It's one of the most fundamental principles of photography. I honestly don't understand all the pushback.
And from the start, your comment had nothing to do with the context of the conversation, since the discussion here is about equivalence. Equivalence is about the same output.

So you could compare a 36" print or fullscreen from an f/2.8 full frame to a 24" print or fullscreen from an f/2.8 APS-C. You wouldn't be discussing equivalence though because you've produced different outputs. And most people I know don't have one monitor or printer for full-frame cameras and a second for APS-C just for the purpose of comparing input specs. Most people have more sense than that.

Your comment is like comparing the spray density of fuel injectors, when someone is actually just concerned with the overall fuel efficiency in mpg. Because exposure is just that: an input spec. It tells you nothing other than light per sensor area. Doesn't tell you anything useful about how much light you've captured. how bright the image is, how much noise there is, etc.
 
And from the start, your comment had nothing to do with the context of the conversation, since the discussion here is about equivalence. Equivalence is about the same output.

So you could compare a 36" print or fullscreen from an f/2.8 full frame to a 24" print or fullscreen from an f/2.8 APS-C. You wouldn't be discussing equivalence though because you've produced different outputs. And most people I know don't have one monitor or printer for full-frame cameras and a second for APS-C just for the purpose of comparing input specs. Most people have more sense than that.

Your comment is like comparing the spray density of fuel injectors, when someone is actually just concerned with the overall fuel efficiency in mpg. Because exposure is just that: an input spec. It tells you nothing other than light per sensor area. Doesn't tell you anything useful about how much light you've captured. how bright the image is, how much noise there is, etc.
OK, I can see what you are saying. Perhaps I'm coming across as trying to be disruptive, though that's not my intention.

Early in this thread I was up front about why I am pressing the point. And I still stand by that. I have seen more than a few posters making misstatements about exposure, based on what they are reading about equivalence. As you know, your original post raised that concern for me. I'm not attacking equivalence, which, to my surprise, is how my posts seem to have been received. I'm left with the impression that mention of exposure is taboo.

Respectfully, I don't agree with your last statements. You say exposure is not relevant to the discussion. I say how can one understand equivalence without an understanding of exposure? Is this really a controversial position?
 
And from the start, your comment had nothing to do with the context of the conversation, since the discussion here is about equivalence. Equivalence is about the same output.

So you could compare a 36" print or fullscreen from an f/2.8 full frame to a 24" print or fullscreen from an f/2.8 APS-C. You wouldn't be discussing equivalence though because you've produced different outputs. And most people I know don't have one monitor or printer for full-frame cameras and a second for APS-C just for the purpose of comparing input specs. Most people have more sense than that.

Your comment is like comparing the spray density of fuel injectors, when someone is actually just concerned with the overall fuel efficiency in mpg. Because exposure is just that: an input spec. It tells you nothing other than light per sensor area. Doesn't tell you anything useful about how much light you've captured. how bright the image is, how much noise there is, etc.
OK, I can see what you are saying. Perhaps I'm coming across as trying to be disruptive, though that's not my intention.

Early in this thread I was up front about why I am pressing the point. And I still stand by that. I have seen more than a few posters making misstatements about exposure, based on what they are reading about equivalence. As you know, your original post raised that concern for me. I'm not attacking equivalence, which, to my surprise, is how my posts seem to have been received. I'm left with the impression that mention of exposure is taboo.

Respectfully, I don't agree with your last statements. You say exposure is not relevant to the discussion. I say how can one understand equivalence without an understanding of exposure? Is this really a controversial position?
You can discuss exposure if you want. Nobody is stopping you, and nobody is arguing against the discussion. But if you want to discuss exposure in the context of equivalence, it must be done in the context of all of the other variables because it is meaningless on its own.

For example, when one talks about focal length in equivalence across formats, it is an input the context of equivalent angle of view--and angle of view cannot be calculated from focal length alone (without also applying the format dimensions). Nobody cares about focal length. They care about the angle of view.

Similarly, when one talks about exposure in context of equivalence across formats, it is an input. What is the corresponding photographic output you hope to get from it? Because every single output also requires mixing the exposure with the format--the exposure on its own is a useless measure.

So go back and substitute the word "focal length" for "exposure" in your original reply to me. The two are analogous to each other in this context. When I said the equivalent photos would be the same, you're essentially saying "Yeah, but the focal lengths are different." And so I'll go back to my first reply: "So?" (So, because the angles of view in the final photo are the same).
 
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Where does he argue that exposure will be dependent on sensor size? Pls give a quote. As far as I see nobody is arguing with that. Exposure and total light are different.
From the start, all I have been saying is that the same scene, shot once on a FF sensor at f/2.8, 1/100s and then again on a cropped sensor at f/2.8, 1/100s are exposed the same. If both are shot at the same iso, they will also be equally bright. Whereas, the exposure is not the same if the ff sensor body aperture is set to f/4.

This shouldn't be controversial. It's one of the most fundamental principles of photography. I honestly don't understand all the pushback.
Correct, they will be have the same exposure and brightness. Nobody argues about that.

But they will not be the same images (not equivalent). Noise levels, DR, DoF will be different.
 
Where does he argue that exposure will be dependent on sensor size? Pls give a quote. As far as I see nobody is arguing with that. Exposure and total light are different.
From the start, all I have been saying is that the same scene, shot once on a FF sensor at f/2.8, 1/100s and then again on a cropped sensor at f/2.8, 1/100s are exposed the same. If both are shot at the same iso, they will also be equally bright. Whereas, the exposure is not the same if the ff sensor body aperture is set to f/4.

This shouldn't be controversial. It's one of the most fundamental principles of photography. I honestly don't understand all the pushback.
Correct, they will be have the same exposure and brightness. Nobody argues about that.

But they will not be the same images (not equivalent). Noise levels, DR, DoF will be different.
I agree completely.
 
You can discuss exposure if you want. Nobody is stopping you, and nobody is arguing against the discussion. But if you want to discuss exposure in the context of equivalence, it must be done in the context of all of the other variables because it is meaningless on its own.

For example, when one talks about focal length in equivalence across formats, it is an input the context of equivalent angle of view--and angle of view cannot be calculated from focal length alone (without also applying the format dimensions). Nobody cares about focal length. They care about the angle of view.

Similarly, when one talks about exposure in context of equivalence across formats, it is an input. What is the corresponding photographic output you hope to get from it? Because every single output also requires mixing the exposure with the format--the exposure on its own is a useless measure.

So go back and substitute the word "focal length" for "exposure" in your original reply to me. The two are analogous to each other in this context. When I said the equivalent photos would be the same, you're essentially saying "Yeah, but the focal lengths are different." And so I'll go back to my first reply: "So?" (So, because the angles of view in the final photo are the same).
The last word is yours. Have a great day.
 
I think the only people who would argue that would be people who don't know how to read.

beatboxa wrote:

A 24-70mm F/4 on a full frame camera is essentially equivalent to a 16-47mm F/2.8 on APS-C in terms of everything. Including DoF, light captured, and shot noise.
Not everything. The exposure is not the same.
The misunderstandings of equivalence baffle me read through DPreviews take on it in the link below. Or for a deeper more comprehensive explanation look at the second link

https://www.dpreview.com/articles/2666934640/what-is-equivalence-and-why-should-i-care

http://www.josephjamesphotography.com/equivalence/

Ignoring how folk mislabel exposure that is a whole other kettle of fish :-) . The bottom line from a photographic perspective is. If you take an image on APS with a 16mm lens at F/2.8 and one on FF with a 24mm.

The resulting image { minor modern sensor differences notwithstanding } . You will have two images with the same diagonal AOV, the same DOF and same total light thus same noise { assuming you increase the ISO to match the shutter speed }. So as far as it goes you will indeed have two equivalent images .
The 16mm on APS-C would need to be f2 to have the same minimum DOF as the 24mm f2.8 goes on FF. Or, if the 16mm APS-C lens is f2.8, then the 24mm FF lens woukd need to be f4.
We were taking about the 24-70mm F/4 :-) As my concluding point below suggests
The statement in your original post above was ambiguous and simply stated that "If you take an image on APS with a 16mm lens at F/2.8 and one on FF with a 24mm" it would have the same AOV and DOF. That reads to me that they you are saying both are f2.8.
So it is perfectly reasonably to say that an F/2.8 lens on APS will do the same job as an F/4 lens on FF
The line at the end of my post which I highlighted for you and is right above this reply . Makes it abundantly clear that I was continuing the discussion about the 24-70mm F/4 . In case this line doesn't make it clear I will reiterate for the sake of pedantry that "it is perfectly reasonably to say that an F/2.8 lens on APS will do the same job as an F/4 lens on FF" :-) You did I presume read the title and content of the OP ? The original title was kept in every post I made and replied to namely "24-70 f4 vs apsc f2.8 lenses"
If this was your write up in a journal or an exam paper, it would be marked down as being ambiguous. You really needed to add in the same sentence that the 16mm f2.8 on APS C would be the "equivalent" of the 24 f4 on FF for AOV and DOF purposes. I mean, if you accept your last premise of tying it all together "So it is perfectly reasonably to say that an F/2.8 lens on APS will do the same job as an F/4 lens on FF" then why even put aperture in the sentence anyway when you said, "If you take an image on APS with a 16mm lens at F/2.8 and one on FF with a 24mm" It just adds to the confusion of how the DOF will be the "same".
 
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I think the only people who would argue that would be people who don't know how to read.

beatboxa wrote:

A 24-70mm F/4 on a full frame camera is essentially equivalent to a 16-47mm F/2.8 on APS-C in terms of everything. Including DoF, light captured, and shot noise.
Not everything. The exposure is not the same.
The misunderstandings of equivalence baffle me read through DPreviews take on it in the link below. Or for a deeper more comprehensive explanation look at the second link

https://www.dpreview.com/articles/2666934640/what-is-equivalence-and-why-should-i-care

http://www.josephjamesphotography.com/equivalence/

Ignoring how folk mislabel exposure that is a whole other kettle of fish :-) . The bottom line from a photographic perspective is. If you take an image on APS with a 16mm lens at F/2.8 and one on FF with a 24mm.

The resulting image { minor modern sensor differences notwithstanding } . You will have two images with the same diagonal AOV, the same DOF and same total light thus same noise { assuming you increase the ISO to match the shutter speed }. So as far as it goes you will indeed have two equivalent images .
The 16mm on APS-C would need to be f2 to have the same minimum DOF as the 24mm f2.8 goes on FF. Or, if the 16mm APS-C lens is f2.8, then the 24mm FF lens woukd need to be f4.
We were taking about the 24-70mm F/4 :-) As my concluding point below suggests
The statement in your original post above was ambiguous and simply stated that "If you take an image on APS with a 16mm lens at F/2.8 and one on FF with a 24mm" it would have the same AOV and DOF. That reads to me that they you are saying both are f2.8.
So it is perfectly reasonably to say that an F/2.8 lens on APS will do the same job as an F/4 lens on FF
The line at the end of my post which I highlighted for you and is right above this reply . Makes it abundantly clear that I was continuing the discussion about the 24-70mm F/4 . In case this line doesn't make it clear I will reiterate for the sake of pedantry that "it is perfectly reasonably to say that an F/2.8 lens on APS will do the same job as an F/4 lens on FF" :-) You did I presume read the title and content of the OP ? The original title was kept in every post I made and replied to namely "24-70 f4 vs apsc f2.8 lenses"
If this was your write up in a journal or an exam paper, it would be marked down as being ambiguous. You really needed to add in the same sentence that the 16mm f2.8 on APS C would be the "equivalent" of the 24 f4 on FF for AOV and DOF purposes. I mean, if you accept your last premise of tying it all together "So it is perfectly reasonably to say that an F/2.8 lens on APS will do the same job as an F/4 lens on FF" then why even put aperture in the sentence anyway when you said, "If you take an image on APS with a 16mm lens at F/2.8 and one on FF with a 24mm" It just adds to the confusion of how the DOF will be the "same".
I was crediting the readers of the post with some common sense. When I read a post in a thread I assume it relates to the topic in hand . Clearly a mistake on my part :-) Your pedantry has reached the level of tedium , thus I will be wasting no more time replying to you

--
Jim Stirling:
It is not reason which is the guide of life, but custom. David Hume
 
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A 24-70mm F/4 on a full frame camera is essentially equivalent to a 16-47mm F/2.8 on APS-C in terms of everything. Including DoF, light captured, and shot noise.
Let's compare 24 mm f4 on FF vs. 16 f2.8 on Dx, assuming same shutter speed and same sensor technology (like shooting with an FF camera either in FF mode or using its Dx crop mode). Here is how I understand what you are trying to say:
  • Angle of view are the same (obviously)
  • DOF is the same
  • The lens at F2.8 will transmit twice as much photons as the lens at F4, regardless of the format used
  • That light is projected over a surface which is a little more than twice as large on the FF camera (we'll call it 2 fold larger to simplify)
  • Therefore the overall number of photons captured by the sensors will be the same, because the collection of photons over a surface which is about twice as large cancels out the difference in apertures.
Is this what your reasoning is?
To avoid confusion, I think it's important to separate inputs & outputs and to introduce focal lengths.

...
It's typical to show the object on the left and the image on the right.
An example from the PhotonsToPhotos Optical Bench :

bc26d7af8b8c43d28c59e01074652595.jpg.png

In this case the distance along the optical axis from F (front focal point) to H (front principal plane) and from H' (rear principal plane) to F' (rear focal point) is 94mm, the focal length.

And the height of P (entrance pupil) of 52.22mm divided by the focal length of 94.00mm is 1.80 the f-number.

BTW, note that P' (exit pupil) is only 43.77mm. Pupil magnification is 0.8 which is mostly important only for close-up work.

For additional basic information see the PhotonsToPhotos Optics Primer .

--
Bill ( Your trusted source for independent sensor data at PhotonsToPhotos )
 
To avoid confusion, I think it's important to separate inputs & outputs and to introduce focal lengths.

...
Regarding Angle of View see this ray tracing:

Best viewed "original size"
Best viewed "original size"

The dark green line is the chief ray and determines the angle of view.

Note that it points from the object side (left) toward the center of P (entrance pupil).

The angle the chief ray makes with I (image plane) only matches the angle of view in rectilinear lenses and when pupil magnification is 1 (not true above).
--

Bill ( Your trusted source for independent sensor data at PhotonsToPhotos )
 
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