Sony E camera + 2.8 zooms = big blow vs other mirrorless. So why none yet?

It's because Sony knows they are king in the mirrorless domain. I am sure they are very capable of creating compact f/2.8 lenses if they were really pressure too, but they are pumping out f4 zoom lenses first to everybody can buy them up.

Then finally after a few years they will release to f/2.8 lenses so people can buy them. If they released f/2.8 lenses now, then nobody will want to buy the f/4 version.

They are maximising profits.

Also since Canon and Nikon aren't serious about mirrorless and Sony is the only one with FF mirrorless, they will probably sit back and make as much money as they can with this strategy as there is no pressure because there is literally no competition.

At this rate they might even release Mk.II versions of the existing f/4 zooms with some gimmicky new lens coating before they release the f/2.8 versions.
well, partly i agree. but partly, it is like asking, hey, why didnt they release A7 10 years ago? or like asking nikon, hey, why release D600 that is a big problem, instead of D750 straight away?

or hey, canon, why not 6D mark 2 last year? well, i believe they are doing their best.

sony engineers/designers are human after all. lack of resources must be one of the reason. we cant hire lens designer at dirt cheap price from 3rd world countries arent we?

heck, if canon/nikon are so great then DSLR sales wont plummeted 35% last year. if fuji oly are as great as they think/claim they are, then they would have beat sony last year in mirrorless, right?

but, heck, imagine the market without sony, either DSLR like canikon or m43 like fuji/oly. feeling something missing? :D
 
So you are saying an f2.8 FE lens when mounted on an aps-c camera will no longer be an f2.8 lens and will need a slower shutter speed for correct exposure which is what lens speed is all about? This surprises me a bit.

You seem to be saying that using f4 on a full frame requires a slower shutter speed (i.e. faster lens) for correct exposure than an f2.8 lens on an aps-c camera. On light meters it says nothing about sensor size.

OK the full frame needs a bigger aperture to expose a larger sensor but the f number is independent of this and the longer focal lengths needed for the same DOF scale up the aperture which is the joy of the f number.
Given this, am just wondering when Sony will intro their standard and tele 2.8 zooms similar to what Fuji and others now offer.
Similar to "X" offers doesn't necessarily mean the same f-number - f/2,8 on M4/3 equals f/5,6 on full frame, f/2,8 on APS-C (like Fuji) equals f/4,2 on full frame. Thus f/4 on full frame is "faster" than f/2,8 on the two smaller formats.

More on the subject of format comparisons here .

--
Abe R. Ration - amateur photographer, amateur armchair scientist, amaterur camera buff
http://aberration43mm.wordpress.com/
 
I was dismayed to see the explanation of the effect of a smaller light cone on DPR!

Oh come on, Mr. Richard Butler, just because a smaller sensor captures a smaller portion of the cone of light does not mean that the light captured is less, from the point of view of the sensor!
Why wouldn't it ?
It is the same amount of light on a per unit of sensor area basis!
Right ... and so over a bigger sensor ... ?
Want to read a more reasonable interpretation? Here's one!
What you call a 'more reasonable interpretation', I call worthless trash.

So anyway, if the "total light" thing really bothers you, you can just agree about the DOF difference and acknowledge that larger sensors have less noise at high ISOs for "some reason" :)

- Dennis
--
Gallery at http://kingofthebeasts.smugmug.com
 
I do have a D700 and much of the Nikkors including the trinity 2.8 zooms.

Instead of getting the D750 I tried out mirrorless and chose the A6000. Am quite happy with it, but do miss 2.8 zooms which are available in the Fuji APC system. The Fuji lenses aren't that big or bulky, esp. when compared to DSLR equivalents.
the fuji lenses aren't that big or bulky because they are only an "equivalent aperture of F5.6" on ff.
Fuji has a 1.5X crop factor, not 2X. So the same f/2.8 lenses for e mount should be the same size as the Fuji lenses.

Sony's dilemma is that it wants to move people up to full frame. With bodies not much over $1000 and equivalent lenses for FF that cost the same as the Fuji lenses (70-200/4 is $100 less than Fuji 50-140/2.8) it's hard to make a compelling case for why Sony wants to invest in making high end options for both APS-C and FF. They'd double up on their investments in certain lenses, but wouldn't double up on the sales.

Nikon and Canon are in the same boat, cutting back on their investments in high end APS-C. I'm sure some people would buy and appreciate these lenses, but it's a much easier decision for Fuji and m43 - they only have one sensor size, and so if they want any high end options at all, that's the sensor size they make them for. Sony, Nikon & Canon have to decide where to put their investments, and it seems they've decided that they'll make more money doing high end stuff for full frame.

Besides, Sony always has A mount via adapter as an option - I think that with the move to ditch the NEX name and explicitly call everything Alpha, they want to push the idea that this is all one big system. If I had occasional need for an f/2.8 lens on e mount, I'd be ok with an adapted A mount lens. If I wanted the equivalent of a 50-135/2.8 for APS-C, I'd have to think hard about spending $1500 on it, knowing I could go FF and get an equivalent lens for the same price. And it doesn't end with that lens ... 35/2.8 pancake for FF at $600 versus 24/1.8 for APS-C at $800 ...

- Dennis
--
Gallery at http://kingofthebeasts.smugmug.com
 
Do you really get it when I say "smaller fov"? We are talking about light intensity, not photovoltaic power generation. F ratio does not take resolution into consideration (nor ISO for that matter) and is purely a measure for the change in intensity of light over the focal distance (decreases at square of distance) - barring losses in transmission, it's the same amount of light per unit of area for the same f ratio, irrespective of the combination of aperture and focal length. Therefore it is a specious argument that conflates DoF with light intensity.

If you need further explanation, think of an FF sensor working in crop mode. With an FF lens, just to make it easier. NOW tell me if the image being captured has "more light", "less light", or the same light as when in FF mode.
 
davelok wrote:

> Do you really get it when I say "smaller fov"? We are talking about light intensity,

Who is "we" ? You're arguing against total light, so talking about both.

> Therefore it is a specious argument that conflates DoF with light intensity.

What is ? Nobody ever said that light intensity changes. Total light does. You started out by saying: >just because a smaller sensor captures a smaller portion of the cone of light does not mean that the light captured is less

And now are claiming that we're only talking about light intensity. You do realize that nobody has ever claimed that a smaller sensor reduces light intensity, right ?

> If you need further explanation, think of an FF sensor working in crop mode.

Or: you think of it. Whether you have many small photosites or fewer larger photosites, either way, the bigger sensor is counting more photons.

> With an FF lens, just to make it easier. NOW tell me if the image being captured has "more light","less light", or the same light as when in FF mode.

It captured less light. And when you blow up the cropped image to the same size print as the full frame image (granted, the FOV will differ) it will appear noisier as a result.

- Dennis
--
Gallery at http://kingofthebeasts.smugmug.com
 
LoL that's funny, because it is all part of the original argument I made.
 
I was dismayed to see the explanation of the effect of a smaller light cone on DPR!

Oh come on, Mr. Richard Butler, just because a smaller sensor captures a smaller portion of the cone of light does not mean that the light captured is less, from the point of view of the sensor!
Why wouldn't it ?
It is the same amount of light on a per unit of sensor area basis!
Right ... and so over a bigger sensor ... ?
Want to read a more reasonable interpretation? Here's one!
What you call a 'more reasonable interpretation', I call worthless trash.

So anyway, if the "total light" thing really bothers you, you can just agree about the DOF difference and acknowledge that larger sensors have less noise at high ISOs for "some reason" :)

- Dennis
--
Gallery at http://kingofthebeasts.smugmug.com
davolek is correct, and I think he has explained it very well in his postings .

There is no 'total' light .
 
Sony has focused on camera bodies, not a on lenses. As an A7 owner I think it's a bit backwards. There's now (after roughly a year) 4 FE mount bodies available while there's been hardly any lenses. Things are progressing though. The 90mm is coming and so is the 28mm.
 
Do you really get it when I say "smaller fov"? We are talking about light intensity, not photovoltaic power generation. F ratio does not take resolution into consideration (nor ISO for that matter) and is purely a measure for the change in intensity of light over the focal distance (decreases at square of distance) - barring losses in transmission, it's the same amount of light per unit of area for the same f ratio, irrespective of the combination of aperture and focal length. Therefore it is a specious argument that conflates DoF with light intensity.

If you need further explanation, think of an FF sensor working in crop mode. With an FF lens, just to make it easier. NOW tell me if the image being captured has "more light", "less light", or the same light as when in FF mode.
Clearly, a FF sensor in crop mode captures less light than that same sensor at the same exposure in FF mode. In crop mode it captures all the light captured by the central 44.444444% of pixels. In FF mode it captures all that light plus all the light captured by the remaining 55.555555% of pixels. In FF mode it captures 2.25 times as much light as it does in crop mode.
 
I was dismayed to see the explanation of the effect of a smaller light cone on DPR!

Oh come on, Mr. Richard Butler, just because a smaller sensor captures a smaller portion of the cone of light does not mean that the light captured is less, from the point of view of the sensor!
Why wouldn't it ?
It is the same amount of light on a per unit of sensor area basis!
Right ... and so over a bigger sensor ... ?
Want to read a more reasonable interpretation? Here's one!
What you call a 'more reasonable interpretation', I call worthless trash.

So anyway, if the "total light" thing really bothers you, you can just agree about the DOF difference and acknowledge that larger sensors have less noise at high ISOs for "some reason" :)

- Dennis
--
Gallery at http://kingofthebeasts.smugmug.com
davolek is correct, and I think he has explained it very well in his postings .

There is no 'total' light .
Davolek is wrong because he is confusing "light intensity" with "amount of light".

If you leave a shot glass and a bucket out in your back yard during a rainstorm that drops 1cm of rain, both will collect about 1cm of rain. And when you empty the shot glass into a measuring cup, you will find it has collected about 10ml of rain. Then when you empty the bucket into a (much larger) measuring cup, you will find the bucket has collected about 300ml of rain.

Fundamentally a digital camera sensor is a two-dimensional array of photon counters. The amount of light captured by a sensor is the total of all the photons its individual counters has counted. A larger sensor will either have more counters or large counters or a bit of each. In the case of equal sized counters, since the photons are arriving at roughly the same rate per counter, over the same period of time, each counter will count roughly the same number of photons, but the total of photons counted on the larger sensor will be larger by the factor of the increase in number of counters. In the case of differetn-sized sensors with an equal number of counters, with the larger sensor having proportionately larger counters, since the photons are arriving at roughly the same rate per unit area, the larger counters will count more photons per unit of time. Since both sensors have the same number of counters it follows that the total of photons counted on the larger sensor will be larger than on the smaller sensor, in proportion to the difference in their sizes.
 
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So you are saying an f2.8 FE lens when mounted on an aps-c camera will no longer be an f2.8 lens and will need a slower shutter speed for correct exposure which is what lens speed is all about? This surprises me a bit.
No, I am not saying that.

What I am saying is that the same exposure across formats creates a different effect, including nosie characteristics.

If you use a f/2,8 lens on APS-C, it behaves like a f/4,2 lens would behave on full frame.
but the f number is independent of this
f-number is the ratio of focal length and entrance pupil diameter.
and the longer focal lengths needed for the same DOF scale up the aperture which is the joy of the f number.
I don't understand what you mean by above.

Anyhow, if you want to understand the concept, I recommend you read this and some of the follow ups.

Abe R Ration, post: 55361508"]
westlites, post: 55361508"]
Given this, am just wondering when Sony will intro their standard and tele 2.8 zooms similar to what Fuji and others now offer.
Similar to "X" offers doesn't necessarily mean the same f-number - f/2,8 on M4/3 equals f/5,6 on full frame, f/2,8 on APS-C (like Fuji) equals f/4,2 on full frame. Thus f/4 on full frame is "faster" than f/2,8 on the two smaller formats.

More on the subject of format comparisons here .
 
Do you really get it when I say "smaller fov"? We are talking about light intensity, not photovoltaic power generation. F ratio does not take resolution into consideration (nor ISO for that matter) and is purely a measure for the change in intensity of light over the focal distance (decreases at square of distance) - barring losses in transmission, it's the same amount of light per unit of area for the same f ratio, irrespective of the combination of aperture and focal length. Therefore it is a specious argument that conflates DoF with light intensity.

If you need further explanation, think of an FF sensor working in crop mode. With an FF lens, just to make it easier. NOW tell me if the image being captured has "more light", "less light", or the same light as when in FF mode.
Clearly, a FF sensor in crop mode captures less light than that same sensor at the same exposure in FF mode. In crop mode it captures all the light captured by the central 44.444444% of pixels. In FF mode it captures all that light plus all the light captured by the remaining 55.555555% of pixels. In FF mode it captures 2.25 times as much light as it does in crop mode.
Just to show that the final results are not that linear, thing about the 12 Mpx D2X FF camera, versus a 24 Mpx APSC A6000.

Yes, the D2X will capture over the whole sensor area 2x times as much photons.

But when I print a picture at 30x60 cm, I will have to enlarge the FF picture 1.4 times as much as as the APSC ones (2x more Mpx, SQR(2) as much resolution), thereby amplifying noise more.

So, disregarding older sensor tech, there is not that much left of the inital gain in noise simply due to total amount of light. Maybe the reason that the A7r is only half a dB worse in SNR than the A7s. The latter is the more practical advantages of lower files sizes, faster processing, faster AF, fully electronic shutter, all due to the lower res.
 
davolek is correct, and I think he has explained it very well in his postings .

There is no 'total' light .
And the earth is flat.

So if a full frame sensor is struck by more photons, during the exposure, than an APS-C sensor, at the same light intensity, what is that, if not 'total light' ? Do you just object to the terminology ? Or do you really think the FF sensor isn't exposed to more light ? And again, I ask, how is it that the full frame sensor shows less noise at a given exposure, if not because it capture more light ?

- Dennis
--
Gallery at http://kingofthebeasts.smugmug.com
 
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I was dismayed to see the explanation of the effect of a smaller light cone on DPR!

Oh come on, Mr. Richard Butler, just because a smaller sensor captures a smaller portion of the cone of light does not mean that the light captured is less, from the point of view of the sensor!
So if I put one cm of butter on top of one sandwich and then one cm of butter on two different sandwiches, the amount of butter used will be equal regardless of if I look at the 1 or the 2 sandwich system?

A crop is a crop regardless of how you crop - and cropping throws away light.
It is the same amount of light on a per unit of sensor area basis!
Sure, but the amount of light collected is different.
It is the same amount of light for the image being captured.
This contradicts directly what you said one line above this :)

Different sized sensors have different amount of sensor area - if a fixed amount of light "per unit area" is used, how can the light captured be the same?
The only thing that's smaller is the field of view!
If you use the same lens the field of views will be different, as well as the amount of light captured. Or are you saying that anything outside of "APS-C" crop on a full frame gets no light at all?
Want to read a more reasonable interpretation? Here's one!
Not really, but you might want too check this out . It should provide a rather comprehensive explanation on the relevant subjects. The relevant mathematical formulas are in the most details article of them.
There is of course one way in which a smaller sensor will have lesser light capture - on a per-pixel basis, if the resolution (and technology etc.) is the same as a larger sensor. The larger sensor's larger pixels will get more light, and there may be other physical or electromagnetic disadvantages for the smaller sensor.
If it is raining and I have a small cup and a large barrell, both get the same exposure to the rain, yet one of them will collect more raindrops.

Noise if almost entirely a function of light - capturing more light increases both signal and noise, but the signal increases much faster, thus the signal to noise ratio (SNR) improves.

This is why big sensors in general are able to outperform the smaller ones when non-identical images are acceptable.
If we compare, say a 16MP APS-C with a 24MP FF, [edit: wrong comparison - area varies in ratio of the square of the diagonal crop factor. Substitute with appropriate resolution difference] the per-pixel light advantage would disappear. However, for an apple to apple comparison, we need to have the same resolution, right?
With equally efficient sensors a FF will capture about 2,25 times more light than a APS-C sensor and the SNR will be 1,5 times better.
Yes, if we view both the images at the same size.
There is usually little point in comparing output images of anything but the same size.
Not if we match the FoV, though there's no reason why you'd want to do that.
Huh, of course you want to match the angle of view. If I want to take a picture of cerain landscape I'll use for example 20mm lens of APS-C and 30mm on full frame. It would be silly to not do so, would it not?
You'd like to view the smaller sensor's higher resolution at comparable viewing size, wouldn't you?
No idea what you mean here. The FF in your example has higher resolution. The APS-C has finer pixel pitch.
The remaining big difference is in terms of the DoF, but if you want a deeper DoF, which one would you prefer, ceteris paribus? With the same lens being used on both sensors, the smaller one will have a greater advantage with sharp centres too, yadda yadda.
Nope - the smaller image of the APS-C (24mm by 16mm or a bit less) will need to be enlarged 1,5 times more than the FF image (of 36mm by 24mm) for the same output image size. Thus the relevant aberrations of the lens are also enlarged 1,5 times more.
Well anyway all of this is not that big a deal. We could avoid much of the confusion if we just started to talk about lenses in terms of Field of View rather than focal length. And stopped applying crop factors to apertures.
The same f-number creates a different effect of different systems - thinking that a cell phone f/2,8 and medium format f/2,8 are somehow the same just might be a bit silly.

The f-number is nothing but focal length divided by the diameter of the entrance pupil. If you change one, the other changes as well.
 
Do you really get it when I say "smaller fov"? We are talking about light intensity, not photovoltaic power generation. F ratio does not take resolution into consideration (nor ISO for that matter) and is purely a measure for the change in intensity of light over the focal distance (decreases at square of distance) - barring losses in transmission, it's the same amount of light per unit of area for the same f ratio, irrespective of the combination of aperture and focal length. Therefore it is a specious argument that conflates DoF with light intensity.

If you need further explanation, think of an FF sensor working in crop mode. With an FF lens, just to make it easier. NOW tell me if the image being captured has "more light", "less light", or the same light as when in FF mode.
Clearly, a FF sensor in crop mode captures less light than that same sensor at the same exposure in FF mode. In crop mode it captures all the light captured by the central 44.444444% of pixels. In FF mode it captures all that light plus all the light captured by the remaining 55.555555% of pixels. In FF mode it captures 2.25 times as much light as it does in crop mode.
Just to show that the final results are not that linear, thing about the 12 Mpx D2X FF camera, versus a 24 Mpx APSC A6000.
The D2X is an APS-C Camera with a 23.7mm x 15.7mm sensor released in 2004. You'll need to come up with a different camera for your example. When and if you do, don't complicate matters with radical differences in sensor technology, unless your point is that difference in sensor technology can also make a difference in amount of light captured. Nobody I know of is denying that, though I'd probably deny that technolody differences in the past 5 years are as significnat as one step up in sensor size.
Yes, the D2X will capture over the whole sensor area 2x times as much photons.

But when I print a picture at 30x60 cm, I will have to enlarge the FF picture 1.4 times as much as as the APSC ones (2x more Mpx, SQR(2) as much resolution), thereby amplifying noise more.
If we had a FF (36mm x 24mm) sensor camera and wanted to print at 40x60 cm we'd need to enlarge by a factor of 600/36 = 16.666:1. If we had an APS-C amera with a 24mm x 16mm sensor ad dwanted to print at the same 40x60 cm size, we''d have to enlarge by a factor of 600/24 = 25:1. So we'd be enlarging the APS-C image 1.5 times as much as the FF image.

I think you need to rework your entire examle and try again.

Or just drop it.
 
Equivalent apertures are not just equivalent, they are the same diameter.

Example:

APS-C: 24mm @ f/2.0 = 12mm aperture diameter

FF: 36mm @ f/3.0 = 12mm aperture diameter

This is the key to equivalence: images taken with the same field of view and the same aperture diameter will have the same DOF and the same total light (with the same shutter speed).

It's really simple and elegant once you understand it.
 
I was dismayed to see the explanation of the effect of a smaller light cone on DPR!

Oh come on, Mr. Richard Butler, just because a smaller sensor captures a smaller portion of the cone of light does not mean that the light captured is less, from the point of view of the sensor!
Yikes! I lost my reply to page refresh! Rewriting.
So if I put one cm of butter on top of one sandwich and then one cm of butter on two different sandwiches, the amount of butter used will be equal regardless of if I look at the 1 or the 2 sandwich system?

A crop is a crop regardless of how you crop - and cropping throws away light.
Bad analogy, but alright. When it comes to crop sensors, you're spreading the butter on a smaller bread. Compare it to your eating an equivalent area from the middle of a bigger slice (some people do that) and throwing away the sides. The real wastage in this case would be the unused FF sensor area, which does not exist in case of the smaller sensor. Using an FF lens on a crop sensor then is throwing away the extra butter. I said I didn't like this analogy.
It is the same amount of light on a per unit of sensor area basis!
Sure, but the amount of light collected is different.
Does not matter. The image is different.
It is the same amount of light for the image being captured.
This contradicts directly what you said one line above this :)
No. Same amount of light for the same view. Look at it from the POV of the smaller sensor - what lies outside its frame does not matter to it.
Different sized sensors have different amount of sensor area - if a fixed amount of light "per unit area" is used, how can the light captured be the same?
The debate is about the light intensity as measured by the f ratio. We are not discussing photovoltaics and the amount of power generated.
The only thing that's smaller is the field of view!
If you use the same lens the field of views will be different, as well as the amount of light captured. Or are you saying that anything outside of "APS-C" crop on a full frame gets no light at all?
The fov will be different between both the sensors unless the larger one uses a longer focal length.
Want to read a more reasonable interpretation? Here's one!
Not really, but you might want too check this out . It should provide a rather comprehensive explanation on the relevant subjects. The relevant mathematical formulas are in the most details article of them.
Your blog was the first one I read, and I didn't find it thoroughly agreeable.
There is of course one way in which a smaller sensor will have lesser light capture - on a per-pixel basis, if the resolution (and technology etc.) is the same as a larger sensor. The larger sensor's larger pixels will get more light, and there may be other physical or electromagnetic disadvantages for the smaller sensor.
If it is raining and I have a small cup and a large barrell, both get the same exposure to the rain, yet one of them will collect more raindrops.
Again, a flawed analogy when it comes to optics. It might look self evident when you describe it as barrels in the rain. What you really have in optics is akin to using a funnel to fill your barrel - the larger the barrel, the wider your funnel needs to be for collecting the same proportion of water. Why? Because the larger your sensor, the wider the image circle, and therefore lesser amount of light per unit area for a given aperture. Therefore, you have to increase the front element size and the focal length, akin to your catchment area. Yes, SNR improves, because you're measuring more photons collected for a given period of time, but the same catchment area would give a smaller sensor a lower f/ratio, upsetting the calculation.
Noise if almost entirely a function of light - capturing more light increases both signal and noise, but the signal increases much faster, thus the signal to noise ratio (SNR) improves.
Yes, the square root of photons collected, but what relationship does it have with the f ratio?
This is why big sensors in general are able to outperform the smaller ones when non-identical images are acceptable.
If we compare, say a 16MP APS-C with a 24MP FF, [edit: wrong comparison - area varies in ratio of the square of the diagonal crop factor. Substitute with appropriate resolution difference] the per-pixel light advantage would disappear. However, for an apple to apple comparison, we need to have the same resolution, right?
With equally efficient sensors a FF will capture about 2,25 times more light than a APS-C sensor and the SNR will be 1,5 times better.
"Amount" of light: irrelevant unless fov matches
SNR: Again, irrelevant in debates about "Aperture Equivalence". Let's keep it restricted to apertures and focal lengths for the purpose of this debate
Yes, if we view both the images at the same size.
There is usually little point in comparing output images of anything but the same size.
Not if you were stuck with a lens of a certain focal length and had to crop the image. Can happen often, you know?
Not if we match the FoV, though there's no reason why you'd want to do that.
Huh, of course you want to match the angle of view. If I want to take a picture of cerain landscape I'll use for example 20mm lens of APS-C and 30mm on full frame. It would be silly to not do so, would it not?
FoV here meant the resultant image, not the capture. But then again, the previous point.
You'd like to view the smaller sensor's higher resolution at comparable viewing size, wouldn't you?
No idea what you mean here. The FF in your example has higher resolution. The APS-C has finer pixel pitch.
That was a bad example as immediately noted alongside. The correct comparison would be 36MP FF vs 16MP APS-C, if you find a pair with matching parameters otherwise.
The remaining big difference is in terms of the DoF, but if you want a deeper DoF, which one would you prefer, ceteris paribus? With the same lens being used on both sensors, the smaller one will have a greater advantage with sharp centres too, yadda yadda.
Nope - the smaller image of the APS-C (24mm by 16mm or a bit less) will need to be enlarged 1,5 times more than the FF image (of 36mm by 24mm) for the same output image size. Thus the relevant aberrations of the lens are also enlarged 1,5 times more.
But would still avoid the aberrations at the extremes. The point then is that an FF lens on a crop sensor is a waste of money if the fov is acceptable.
Well anyway all of this is not that big a deal. We could avoid much of the confusion if we just started to talk about lenses in terms of Field of View rather than focal length. And stopped applying crop factors to apertures.
The same f-number creates a different effect of different systems - thinking that a cell phone f/2,8 and medium format f/2,8 are somehow the same just might be a bit silly.
Comparing the two as if a real life application existed isn't very smart either. Let's not measure outside boundary conditions.
The f-number is nothing but focal length divided by the diameter of the entrance pupil. If you change one, the other changes as well.
Yes, your typical, non-exotic, everyday ratio. The first thing I learnt about photography when I wanted to purchase a system camera.
 
Same total light is a red herring. The smaller sensor has no use for the light that falls outside its physical area. What really matters for the sensor is the intensity of light, which for a given f ratio is the same.

Turn it around and a crop sensor user would be justified to think why one would need to invest in a full frame and its larger lenses just to achieve the same fov and exposure achievable with less (SNR notwithstanding, DoF notwithstanding, not the point here). Unnecessary conflation needs to be avoided. If we bring in economics, which is a stand-in for resource use, a scientific consideration, what serves the purpose better on a dollar-to-dollar basis, if scale disadvantage were to be removed?

If current sensor technology were to hit a ceiling in terms of pixels per mm, we would be forced to think in film terms. Let's say we have a choice of fixed lens cameras with fast primes. Want a wide field of view with good amount of detail, let's say for landscapes? Get a large format film. Want a narrow field of view and a small size, let's say for headshots? Get a smaller format.
 
Same total light is a red herring. The smaller sensor has no use for the light that falls outside its physical area. What really matters for the sensor is the intensity of light, which for a given f ratio is the same.

Turn it around and a crop sensor user would be justified to think why one would need to invest in a full frame and its larger lenses just to achieve the same fov and exposure achievable with less (SNR notwithstanding, DoF notwithstanding, not the point here). Unnecessary conflation needs to be avoided. If we bring in economics, which is a stand-in for resource use, a scientific consideration, what serves the purpose better on a dollar-to-dollar basis, if scale disadvantage were to be removed?

If current sensor technology were to hit a ceiling in terms of pixels per mm, we would be forced to think in film terms. Let's say we have a choice of fixed lens cameras with fast primes. Want a wide field of view with good amount of detail, let's say for landscapes? Get a large format film. Want a narrow field of view and a small size, let's say for headshots? Get a smaller format.
Dave's thoughts on crop digital and the film days above struck me in relation to my A6000.

Am not that familiar with Canon DSLR, my last Canon DSLR was the EOS 20D.

But both Canon and Nikon began with crop DSLRs with lenses optimized for digital in the crop format. Canon was first with widely available FF digital, took Nikon a little more time to get into FF with its D3. Before that, Nikon pros used fast crop Nikkors and film era AF glass to eke out the best IQ from the early 4, 6 and 8 mp sensors.

When Nikon got to FF and 12 mp sensors, the relatively long run of Nikon pro crop bodies meant it already had a substantial body of fast crop (or DX size) glass and it became busy fleshing out its FF (FX size) digital glass. Of course it was simpler for Nikon and Canon, because they could always update their AF glass from film days to digital.

My first mirrorless, for my needs as a non-pro, the A6000 is already near my sweet spot for AF performance since I don't intend to document night-time muggings anyway. For my shooting which is family events in various light, if I had the E mount glass available to me with Nikkors on my D700, the A6000 can already meet my needs.

In Nikon world, I went from D40x to D90 to D300 before becoming happy with the D700. That the A6000 can match up to the D700 for my own needs is very impressive to me. And I do see testimonials from pros using the A6000 (hopefully, not all mercenary), who are happy with its results.

If Sony would provide equivalents to Fuji's and Samsung's offerings, including standard to mid-telephoto 2.8 zooms, I really feel Sony E would attract more switchers from existing mirrorless users and prospective DSLR buyers.
 

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