neither if you get it.
this image was shot with a 300mm lens. it is not a composite
you could get the exact same field of view with a 150 lens on m43. corner to corner you would see exactly the same thing with one large difference - the sun itself would be smaller. why? because it's a 150mm lens cropped to give a 300mm field of view due to the smaller sensor size, not an actual 300mm lens. focal length = The distance between the center of a lens or curved mirror and its focus.
i'm hoping you get it now.
I've got it. There would be slight differences, due to different aspect ratios of the images (W/H: mFT = 1.33, FF = 1.5). However, the image produced by the 150mm lens would be exactly half the linear size (horizontal or vertical dimension) of the 300mm lens, no matter what camera the lens is mounted on.
In the example image that applies to the buildings
and the sun. All of the objects would be rendered 2:1, with the 300mm compared to 150mm lens.
Since the mFT image size is ~1/2 the linear size of FF, the rendered image of the 150mm lens on an mFT camera will be proportionately about the same as a 300mm on a FF camera. That is, the objects appearing in the mFT image
relative to the total image width or height, will be the same as the
relative size in the FF image. The width of the sun ball would occupy the same
relative proportion of the width of the image in both versions, mFT and FF.
Mathematically, 1/2 divided by 1/2 is 1. It comes out the same, relatively speaking.
I don't have handy any photos demonstrating this, but I can easily produce them if it would help.
JRA
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Artists must not only see, but see what they are seeing.