Great Bustard
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Neither perspective, framing, nor DOF are properties of the lens -- they are properties of the system .But he is talking about the lens.OK, well, this is an important point -- I'm talking about the photo. As you may, or may not, have read in my entry into this thread:
So, no, the lens does not change -- no one says it does (I mean, how could it?). But the effect of the lens most certainly does change.
I am talking about the photo that is made with the lens and the body it is used on. What other possible interest could I have in the lens except as it pertains to the photos created with it?
As a photographer, what interest do I have in a lens except in the context of the photos it produces on the body it is used on? The lens, by itself, does not create a photo -- the system the lens is used on creates the photo, and it is how the lens performs on the system that it is used on that is the relevant matter.No, but that also has nothing to do with framing or perspective. How we chose to frame a subject has nothing to do with the lens. We make our framing choice regardless of the lens. Same with perspective. We can chose and lens we like for the picture. There is no point comparing two different lenses... But he isnt, he is comparing the same lens.
Fair point, and I don't disagree. But it is important to realize that the efficiency of the sensor has two components: QE and read noise, where the QE is the proportion of photons falling on the sensor that get recorded (and directly influences the photon noise), and the read noise is the additional noise added by the sensor and supporting hardware.But you see, between the two, the sensor improved. Nothing more. All image quality improvements will have everything to do with the sensor and processing and nothing to do with photon shot noise which has been a constant since photography began.The D40 has ridiculously poor QE:
So, absolutely, in that particular case, the more efficient sensor in the D7000 which has double that amount will result in double the light being recorded for a given exposure (and thus only 71% the apparent photon noise), which is the primary element of the noise in the photo.
The photon noise is the dominant source of noise in a photo (unless the photo is mainly dark, and then the read noise is the dominant source of noise). The role of the sensor in photon noise, as I said above, is the QE.Nope, but this is performance for current technology. We may see performance gains with new tech. We will see performance with processing.In other words, photon noise is dominant, but the QE of the sensor plays a role in the photon noise. However, the maximum possible QE is 100%, and the best modern digicams are hovering around 50%, so we're not going to keep on seeing doublings in performance.
It's a weird way to put it, Ab. The bulk of the noise we see is photon noise, which is from the light itself, which is made worse by the fact that the QE of the sensor is not 100% (and also the fact that the sensor is RGGB rather than each pixel recording all photons).We dont need to see ANY data about sensor efficiency. I simply makes my point, a great deal of the noise we see in imaging is sensor noise.
Usually, when one speaks of the "sensor noise", they mean the additional noise added by the sensor and supporting hardware, which is different from the photon noise.
It really isn't. The primary elements of noise in a photo are:Oh, i know how it works, It really isnt that complex.
- the total amount of light that falls on the sensor (Total Light = Exposure x Sensor Area)
- the proportion of that light that is recorded by the sensor (QE -- Quantum Efficiency)
- the additional noise added by the sensor and the supporting hardware (read noise)
Each party always thinks that of their "opponent".It is just that you do enjoy arguing a point slightly to the left of the main subject and enjoy dictating the terms of the discussion.
Art and science are not mutually exclusive.Photography remains an art, not a science,