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The data in the last bit here is coming from the fact that Nikon clips blacks, which imprints data from higher bits into the last bit. This was explained long ago:
10 bits? Bah humbag. I hear some people still use Windows 3.1 on matching video cards. No more than 8 bits is ever needed.Here is, for entertainment, last bit of a 12-bit camera. Why do we have 12 bits in it anyway? Let's reduce it to just 10.You're just counting angels on the head of a pin... Iliah is saying there are 433 and you're saying that it's only 432 and 433rd one is not a real angel![]()
You have forgotten 640KB RAM, or was it just 64KB?10 bits? Bah humbag. I hear some people still use Windows 3.1 on matching video cards. No more than 8 bits is ever needed.Here is, for entertainment, last bit of a 12-bit camera. Why do we have 12 bits in it anyway? Let's reduce it to just 10.You're just counting angels on the head of a pin... Iliah is saying there are 433 and you're saying that it's only 432 and 433rd one is not a real angel![]()
In the image that was overexposed (shot right after this one) the last bit contains no image data.The data in the last bit here is coming from the fact that Nikon clips blacks, which imprints data from higher bits into the last bit.
Thanks Emil Martinec ... Your saved the dayThe data in the last bit here is coming from the fact that Nikon clips blacks, which imprints data from higher bits into the last bit. This was explained long ago:
http://forums.dpreview.com/forums/read.asp?forum=1021&message=28196804
ROTFLMAO You really do not understand what my answer here http://forums.dpreview.com/forums/read.asp?forum=1042&message=39634256 means?Thanks Emil Martinec ... Your saved the day![]()
Not true: "The data in the last bit here is coming from the fact that Nikon clips blacks, which imprints data from higher bits into the last bit."I think you're missing the point. That is the last bit of data, and it still has details, so clearly, no matter how small or how large, 14bits provides more info than 12bits.Now post the 12-bit shot. You need both to demonstrate the difference
Right, because it does not suite your agendaNot trueI think you're missing the point. That is the last bit of data, and it still has details, so clearly, no matter how small or how large, 14bits provides more info than 12bits.Now post the 12-bit shot. You need both to demonstrate the difference
64KB?! You are wasteful! Let's go all the way! Timex Sinclair ZX-80 baybeee! Whole 1 KB! OK, block characters but it proves we don't need no stinkin 14-bit RAW filesYou have forgotten 640KB RAM, or was it just 64KB?10 bits? Bah humbag. I hear some people still use Windows 3.1 on matching video cards. No more than 8 bits is ever needed.Here is, for entertainment, last bit of a 12-bit camera. Why do we have 12 bits in it anyway? Let's reduce it to just 10.You're just counting angels on the head of a pin... Iliah is saying there are 433 and you're saying that it's only 432 and 433rd one is not a real angel![]()
Oh you so right. Back to lilliputians we go.64KB?! You are wasteful! Let's go all the way! Timex Sinclair ZX-80 baybeee! Whole 1 KB! OK, block characters but it proves we don't need no stinkin 14-bit RAW filesYou have forgotten 640KB RAM, or was it just 64KB?10 bits? Bah humbag. I hear some people still use Windows 3.1 on matching video cards. No more than 8 bits is ever needed.Here is, for entertainment, last bit of a 12-bit camera. Why do we have 12 bits in it anyway? Let's reduce it to just 10.You're just counting angels on the head of a pin... Iliah is saying there are 433 and you're saying that it's only 432 and 433rd one is not a real angel![]()
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Yes, it means that data in the last bit is not correlated with image data in the higher bits, as it was in the image you posted. In neither case is there independent information in the last bit.ROTFLMAO You really do not understand what my answer here http://forums.dpreview.com/forums/read.asp?forum=1042&message=39634256 means?Thanks Emil Martinec ... Your saved the day![]()
Correct. It is independent image data, and it depends on exposure and scene dynamic range, as it should.Yes, it means that data in the last bit is not correlated with image data in the higher bitsROTFLMAO You really do not understand what my answer here http://forums.dpreview.com/forums/read.asp?forum=1042&message=39634256 means?Thanks Emil Martinec ... Your saved the day![]()
Some Nikons (eg the D300) show improved shadow performance in 14-bit mode. This doesn't necessarily mean that it is due to an intrinsic advantage of the higher bit depth, rather 14-bit and 12-bit capture modes are done quite differently, as evidenced by the change in frame rate; the improvement is due to different data capture and processing, and not due to the bit depth of the data storage. This is easily verified by taking a 14-bit capture and truncating it to 12 bits, and comparing the result to the camera set to 12-bit capture.Not true: "The data in the last bit here is coming from the fact that Nikon clips blacks, which imprints data from higher bits into the last bit."I think you're missing the point. That is the last bit of data, and it still has details, so clearly, no matter how small or how large, 14bits provides more info than 12bits.Now post the 12-bit shot. You need both to demonstrate the difference
http://forums.dpreview.com/forums/read.asp?forum=1042&message=39634121
There is no benefit to 14-bit RAW, and it is especially true once you leave the base ISO and go higher (and by the way Thorn Hogan seemed to think 14-bit is more helpful at higher ISO ... LOL. The complete opposite. That just goes to show that he has no real understanding about the topic).
Again: In neither case is there independent information in the last bit, not already contained in higher bits.Correct. It is independent image data, and it depends on exposure and scene dynamic range, as it should.Yes, it means that data in the last bit is not correlated with image data in the higher bitsROTFLMAO You really do not understand what my answer here http://forums.dpreview.com/forums/read.asp?forum=1042&message=39634256 means?Thanks Emil Martinec ... Your saved the day![]()
Rhetorical questions: how many bits can be stripped from 12-bit capture? From 14-bit capture? That is, without the loss of image quality?In neither case is there independent information in the last bit, not already contained in higher bits.
Another poster on Pentax SLR forum (Gordon) did exactly that with K-5, (truncated 14-bit into 12-bit) and found no difference in IQSome Nikons (eg the D300) show improved shadow performance in 14-bit mode. This doesn't necessarily mean that it is due to an intrinsic advantage of the higher bit depth, rather 14-bit and 12-bit capture modes are done quite differently, as evidenced by the change in frame rate; the improvement is due to different data capture and processing, and not due to the bit depth of the data storage. This is easily verified by taking a 14-bit capture and truncating it to 12 bits, and comparing the result to the camera set to 12-bit capture.Not true: "The data in the last bit here is coming from the fact that Nikon clips blacks, which imprints data from higher bits into the last bit."I think you're missing the point. That is the last bit of data, and it still has details, so clearly, no matter how small or how large, 14bits provides more info than 12bits.Now post the 12-bit shot. You need both to demonstrate the difference
http://forums.dpreview.com/forums/read.asp?forum=1042&message=39634121
There is no benefit to 14-bit RAW, and it is especially true once you leave the base ISO and go higher (and by the way Thorn Hogan seemed to think 14-bit is more helpful at higher ISO ... LOL. The complete opposite. That just goes to show that he has no real understanding about the topic).
A non-rhetorical question: The newer Sony's 24 MP sensor has smaller pixels than the old 16MP sensor. Wouldn't that make 14-bit even more useless? In other words, is there a correlation between pixel size and bits required to capture data?Again: In neither case is there independent information in the last bit, not already contained in higher bits.Correct. It is independent image data, and it depends on exposure and scene dynamic range, as it should.Yes, it means that data in the last bit is not correlated with image data in the higher bitsROTFLMAO You really do not understand what my answer here http://forums.dpreview.com/forums/read.asp?forum=1042&message=39634256 means?Thanks Emil Martinec ... Your saved the day![]()