If you had read the entire question, you would have known that the OP was simply asking whether the diameter should be calculated with the actual focal length or the 35mm equiv. focal length. The most direct answer is "use the actual focal length", but somehow you see the need to answer with a 100 page document that doesn't address the question at all.Hmm, here's the OP (bold emphasis mine):The OP asked only about exposure. An explanation is needed, but on optical geometry. The things you mentioned are completely irrelevant to exposure....you need some sort of explanation to accompany your arithmetic above. Your calculations give the aperture diameter, which, of course, is the relevant quantity for a given AOV (angle-of-view) in terms of both the DOF (depth-of-field) and the total light projected on the sensor (for a given shutter speed).
http://forums.dpreview.com/forums/read.asp?forum=1018&message=38250332
There is a few things i just cannon understand about aperature. I hardly belive that my sx100is can have larger aperature than 18-55 nikon. I understand that it is f/2.8, so what i want to know: on wide open canon f/2.8 if the focal lenght is 6mm does it mean that diameter of pupil will be 6/2.8 = 2.14mm, or do i need to calculate its 35mm focal lenght, 30/2.8= 10.7mm? But that means that on 300 it will be 300/4.3= 69mm, which is imposible. I really need some explanation on that.
This is exactly why you're a fanatic...because you truly believe that your 100-pages of practically incomprehensible writings actually answers the OP's question...IT DOESN'T! Nowhere on that web page is there anything resembling, "...is calculated using the actual focal length of the lens, not the 35mm equivalent focal length."...to disregard what was asked, and lash out against anyone explaining what is going on and what relevance it has, is a bit tiring. But, well, it's what you do.
.