Shay Stephens
Forum Pro
Ok I think I have your formula down:
The amount of reflected light is the .18
The (1.0/2.2) is the gamma ratio? And it equals .454545
.18 to the power of .454545 = .459
.459 multiplied by the full range of possible grayscale output (.459*255) = 117
So printing a gray card using RGB 117,117,117 would most closely match the actual shade of a gray card? Has anyone tried this yet? How is the exposure when spot metered and the EV set to 0EV?
Just trying to figure out the specifics here, and I appreciate your including the formula very much.
Shay
My Sony F707 Gallery: http://www.shaystephens.com/portfolio.asp
The amount of reflected light is the .18
The (1.0/2.2) is the gamma ratio? And it equals .454545
.18 to the power of .454545 = .459
.459 multiplied by the full range of possible grayscale output (.459*255) = 117
So printing a gray card using RGB 117,117,117 would most closely match the actual shade of a gray card? Has anyone tried this yet? How is the exposure when spot metered and the EV set to 0EV?
Just trying to figure out the specifics here, and I appreciate your including the formula very much.
--The luminance that comes out of you monitor is not linear in RGB
vaule--this is to do with the gamma of the monitor. The color
matching done by all printers compensates for this fact by not
being linear either. Assuming a gamma of 2.0(back of envelope
standard) -> 2.2(srgb) and inverting the resultant equation gives a
solution of the RGB value needed to give a 18% gray card:
[0.18 ^ (1.0 / 2.2)] * 255 = 117
[0.18 ^ (1.0 / 2.0)] * 255 = 108
Shay
My Sony F707 Gallery: http://www.shaystephens.com/portfolio.asp