## cpw's recent activity

• Yes, I will leave it to you guys to figure out how much charge density you can have, that wasn't my point.  As I said, I assumed that parameter would be unchanged.  What I'm talking about is ...
• Hi Iliah, Here's my speculation.  Since stacking has been shown to be viable in circuit design, I would envision having a 4-layer stacked system (B as top layer, followed by G, then R, then ...
• Replied in D5 FWC
Hi Jim, Haven't talked in awhile.  I always like your measurements, but I'm not following your fwc vs iso graph.  If you get say 130,000 e at iso 100, then at iso 200 I'd think you would get ...
• Yep, thanks Alan, nicely stated. Chris
• Hi Detail Man and Jack, I meant parallel.  So I guess I didn't explain too well, but here is a drawing: You can see the spherical principal surface, and I've drawn this for the case of theta`=24 ...
• Replied in Yes: 0.5
Thanks Jeff, yes this is an extreme situation indeed!  Practicality will set in before these extreme rays can make it through the system, but at least it shows the limitations.  Also, this says ...
• No, the only thing that's required is a well corrected lens and the spherical principal surface. If you draw 'that triangle' correctly, as I have described, then H = f , that's the key, f is on the ...
• Hello, It doesn't seem like you guys are listening to everything I wrote above.  From my original post and others in the past, F# = f/d as well as sin(theta) = 1 / (2*F#) = NA are all ...
• You're welcome DM! Chris
• Hi Detail Man, they are curved in general, the degree to which they are spherical depends on their correction.  The notion of the flat principal surface, or principal plane comes into it when ...
• Hi Detail Man, The approximation occurs when you have a flat principal plane in the derivation, and that leads you and Wikipedia to include arctangent in the derivation right off the bat (the use ...
• Replied in Yes: 0.5
Hi, Jack, Nakamura correctly writes down the formula for F#, but as JACS points out doesn't say where it comes from. It comes from a well corrected lens satisfying the Abbe sine condition, thereby ...
• Hi Detail Man, Thanks for the kind words.  As I look at my past references, I see that the last one that I listed has a broken link; I have since found it again, which is here ("Fundamentals of ...
• Pretty cool Joofa, looks like they're doing some innovative stuff there! Chris
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