olliess wrote:
Bobn2 wrote:
olliess wrote:
I found "invoking" his site useful to this discussion, since it got you to make some substantive comments beyond "I don't agree, your method conveys no information."
This camera 'diffraction limit' nonsense comes from McHugh, and when you find someone completely confused about diffraction, it is generally because they have been reading that site.
The arguments you presented in response to McHugh reveal a lot more about your level of confusion than his. You continue to be confused in your present post:
It only shows that the confused stick together. You have eaten McHugh's nonsense whole and now won't give it up. He and you are confused, not me.
Why did you choose 0.8 times the peak - there is no logic to that.
You quoted the passage where I explained this (the very first time around) quite a number of times, but apparently never fully read/understood it:
"Pick a threshold for a "significant" decrease in resolution.
For argument's sake, I'll pick 0.80 relative to the maximum,
which I'm pretty sure would be noticeable."
'For arguments sak' means 'arbitrary'. You have presented no argument as to why 0.8 is significant, nor why 0.8 of different quantities would be equally significant. So, it is an arbitrary number, picked out of a hat, and arguments based on it mean nothing.
In McHugh's case, his limit is arbitrary and just silly. A complete nonsense. It's a coincidence that yours and his coincide.
In my original post, I did say it was a coincidence. When you work out the math, however (e.g., by convolving the Bayer/AA filter with the Airy disk), you'll see why numbers are close and also why they seem reasonable.
Let's see your 'math' convolving the Bayer/AA filter with the Airy disc. Have you done it, or are you just talking about it?
Anyway, look at the curves again:
And another set
Notice that the position of the peak does dont depend on the pixel count.
You're still arguing about something which nobody is disputing: that the graphs show the peak to be at the same aperture no matter what sensor is used.
Good, so where is this 'diffraction limit'?
What I'm arguing about is what the graphs ALSO show: that the sensor with higher resolution loses more resolution due to diffraction. Not just in absolute resolution, but also in percentage of maximum resolution, meaning that the higher resolution sensor is not just "losing more because it had more to give."
It is exactly losing more because it had more to give. In any case, there is still no 'limit', which you and McHugh say there should be. The point is that as you increase pixel density, you get closer and closer to extracting all that the lens can give, including both aberration and diffraction blurring. We are still someway off extracting all that lenses can give with current pixel densities, even to f/16 on FF (or the same DOF on other formats)
Not also that there is no sudden drop when the 'limit' is reached.
Sorry, your 0.8 rule is as useless as McHugh's caculator.
This is why a "limit" needs to be defined using a "threshold." This is a standard way of defining limits, ranges, differences, etc. in science and engineering measurement.
If you don't understand the reasons why measurements are done this way, then ask. Just repeating that it's useless is, well, useless.
This is ultimately the point. Your 'limit' defines something that cannot be observed, that is arbitrarily defined for no cogent reason. It is nonsense, and worse than nonsense, confuses people into thinking that high pixel densities produces images with more diffraction blur than lower pixel count sensors. So, it is practically useless and confuses people into believing something that is not true - so worse than useless.
If such an aperture exists, then I know I will have to begin trading away maximum sharpness if I want more DOF.
Such an aperture doesn't exist. You can learn the peak aperture from lens to lens, go past that and you're below 'maximum' sharpness. And you trade away maximum sharpness for DOF always, that is a fact of life.
First of all, it seems inconsistent to argue against thresholds and then invoke DOF, since DOF is only meaningful when there a "threshold" has been defined for what is "acceptably sharp."
I didn't argue for any particular threshold for DOF, choose your own CoC, but what I said is always true whatever DOF decision you make, you trade DOF for maximum sharpness.
Secondly, since the effects of defocus and diffraction are combined, it follows that a smaller aperture could, at least in principle, result in less maximum sharpness AND less DOF.
Also not true. You will only get 'maximum sharpness' at the point of focus, and if the lens is essentially diffraction limited, that sharpness will be defined by diffraction
plus the pixellation blur (which decreases as pixel density is increased)
... if the airy disk is 2-3 pixels or larger, diffraction is limiting resolution,
If one wants to be as technically precise as you seem to like, diffraction is
always "limiting" resolution, because it will reduce any resolution "measurement" whether the airy disk is 0.2 pixels or 2.0 pixels wide. The question is, when does it start to limit resolution in a meaningful way?
Could you explain the use of the word 'meaningful' in this context?
In this context it means "in a visually noticeable way."
Lets see you perceptual evidence than that 0.8 of whatever happened to be the maximum is 'visually noticeable'. You have none. So, once again, nonsense.
Are you are arguing that a visual impact will be noticed at some point beyond that where resolution is measurably affected?
Resolution is measurably affected anywhere past the peak for that lens...There is no requirement for the Airy disc to have any particular relationship to pixel size. That is a fiction, and this 'diffraction limit' as calculated by that calculator does not exist.
I'm guessing what you're trying to say here is that there is no special relationship between the Airy disk size in pixel widths and a visually noticeable limit.
What I'm trying top say is what I said.
I don't know whether McHugh got his 2--3 pixel limit empirically,
Why defend it then, yet another arbitrary figure.
Why is it 'reasonable'. lets have some hard perceptual evidence that 2-3 pixels width will suddenly produce 'visible diffraction'. You can't cite it because there is none.
when you work out the interaction between the Bayer/AA filtering and the Airy disk of about that size and then look at what happens to the MTF50.
How does that show this to be 'reasonable'? All you are saying is McHughs guess (as to a phenomenon that does not exist) is similar to your guess (as to a phenomenon which does not exist), which is not surprising, since your guess is directly inspired by McHugh's guess. If you had truly don the 'math' to convolve the diffraction PSF with the AA PSF you would no that there is no such 'limit' when the diffraction blur suddenly becomes visible. If there were there would also be a limit at which lens aberrations suddenly become 'visible', yet I don't see anyone talking about the aberration limit.
(even if the convolution pf point spread ficntions worked in a simple pixel by pixel way, which it doesn't).
The "convolution pf point spread ficntions?" Is this a technical term?
Yes. It's the maths that you need to do if you want to calculate the combined effect of diffraction and pixellation - take the PSF for each and convolve them.
I'm familiar with the maths.
You don't give any evidence of being so.
What you original said was a jumble.
No, I had some types, I typed 'pf' for 'of' and 'ficntions' instead of 'functions'. Less that it was not at all a jumble, it just says 'even if the convolution of point spread functions worked in a simple pixel by pixel way, which it doesn't', which is not at all jumbled. It just says that the convolution of the point spread functions (which is what you need to do to find the combined effect) doesn't work on a simple pixel by pixel basis, which indeed it doesn't. Were you truly 'familiar' with the maths you would know that and understand what I was saying straight away.
Now that you've clarified, I can guess that you meant "convolution of point spread functions." See the above.
That was such a hard guess to make.
Your example doesn't show anything about when diffraction becomes "visible." To do that you need to show us how you determined the threshold for visibility.
Which will depend on the size you present the image. There is no reason at all to think that it becomes 'visible' when it drops to 0.8 of its peak, or any other arbitrary proportion.
You agreed yourself in an earlier post that a resolution difference of 17% was probably "not that noticeable." Pick 0.85 or a higher threshold if that feels safer to you.
If there is a 'threshold' it is not a proportion of the maximum MTF50. What it is is an output resolution relative to a given output image size - that is it depends on how big you view the image and not what is the peak resolution of the lens. Defining it in terms of peak resolution of the lens is absurd.
...as the diffraction limit is approached, the first signs will be a loss of resolution in green and pixel-level luminosity....
As diffraction progressively blurs an image the Bayer artifacts become smaller not larger because the diffraction high pass filters the optical signal meaning that the Bayer array increasingly oversamples.
Diffraction
low pass filters the optical signal. If it high passed the optical signal, it would increase the resolution, in which we'd love it. Read up on the MTF of the Airy disk pattern.
Sorry, miss type - substitute 'low pass filter' - it's like having an extra AA filter, mitigates the effects McHugh claims that it emphasises.
The charts you showed suggest that a sensor array with higher spatial resolution is proportionally MORE affected by diffraction.
No, it suggest that a sensor array with higher spatial resolution gets closer to capturing the full resolution given by the lens.
Since the array of green pixels has higher resolution than the red and blue arrays, respectively, it stands to reason that green (and luminosity) would be more affected, so what he is saying seems correct, although I'm not sure how much you'd notice this.
I would be wary of using the term 'stands to reason' when your arguments are so devoid of it. What matters is not how far off the peak of whatever lens it is, but whether it is sampling above the Nyquist limit for the applied signal, and as diffraction moves the Nyquist limit down the Bayer sampling becomes more and more securely oversampled. So far from what he is saying being 'correct' it is tosh, like most of what he says.
In the sense that differences between luminosity and red/blue resoution produce "artifacts," then sure, diffraction mitigates the artifacts. So would a stronger AA filter, or maybe just a more blurry lens.
You can't have it both ways.
From the example you showed, a smaller pixel (higher resolution) was associated with more reduction of resolution (both relative and absolute) due to diffraction. So he's actually right.
No, it's cobblers.
I can't help it if you don't agree with what your own data show.
It's cobblers. My data doesn't show that rectangular pixels show 'more diffraction' in one direction than another, what they would show is that rectangular pixels capture less resolution in one direction than another, and that applies to any image. You might as well say they show more camera shake in one direction than another, more lens aberrations in one direction than another, more defocus in one direction than another and so on. It's cobblers.
The form below calculates the size of the airy disk and assesses whether the camera has become diffraction limited.
As said previously, a camera does not become 'diffraction limited'
Re-stating what you previously believed doesn't make it any more true. Certainly, the arguments you've presented don't support your view.
And hanging on to McHugh's nonsense doesn't make that any more true, either. You cannot pick a 'diffraction limit' where either you or McHugh claims it is from the MTF curve.
The limit does not exist. His specious but pretty diagrams don't make it exist.
If you want to measure effects then you're probably going to need to define thresholds.
Why, you only define 'thesholds' where they exist. Lets define a 'threshold' of 40MPH and say that a 2CV is as fast as a Ferrari. Absurd reasoning, isn't it?
This is not rocket science.
Certainly it isn't. It's mumbo jumbo pseudo science.
I can plot the MTF curve of the (Bayer filtered) sensor and identify some threshold, such as the MTF50. Then, I can multiply it with an MTF for ideal diffraction for various pixel widths and look at how much the MTF50 has shifted. Then you can compare to your threshold for the change in MTF50.
Exactly the principle of GIGO. Define a meaningless threshold and you get a meaningless result.
On the other hand, if you insist that no threshold is "safe" (zero tolerance for diffraction!), then go ahead and shoot at optimum aperture all the time (or just ignore diffraction).
No, just know how much diffraction will degrade your image and decide whether it is acceptable to you. The acceptability would depend on whether you want to use the image for the web, or for large prints and on your own standards of sharpness. 80% of what you might have had is absurd, and leads people to the notion that they are better off losing 20% of a little than keeping 80% of a lot. Silly, silly reasoning, and leads to widespread misunderstandings we see all over these forums. You and McHugh should just stop it.
It's your perfect right to hang on to this nonsense if you want, but it's still balls, and I for one will do what I can to properly inform less gullible photographers.
Go for it. Just don't keep misreading (or failing to read) stuff and then spend pages arguing about how wrong it is.
I have read and understood it and it is nonsense.
As to whether the arguments I've presented support my view, well I wouldn't expect someone who thinks you can find a 'limit' by applying an arbitrary quotient to understand reasoned argument.
The little personal jabs are actually kind of comical.
Check back and see who started the 'little personal jabs'. It wasn't me. So if comical they are, the joke is on you. Especially since everyone who actually knows anything about the topic of diffraction knows you are talking garbage.
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Bob