Why can't I do this with my GH3?

Started 3 weeks ago | Questions thread
Kawika Nui
Regular MemberPosts: 306
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Re: Why can't I do this with my GH3?
In reply to tt321, 3 weeks ago

tt321 wrote:

Kawika Nui wrote:

Chez Wimpy wrote:

Kawika Nui wrote:

john isaacs wrote:

This photo does not look like it was taken "hours before dawn". An ISO100, 1/13sec f3.2 shot has got a lot of light. Look at the clouds, they're getting sunlight. The sky is pink. Looks to me like the sun's about to come up.

Thanks for sharing. Luckily, your opinion is just...your opinion.

"Looks to me like" phrasing might indicate an opinion, but your P&S exposure was for roughly 7 EV which means there was sunlight filtering through to light the scene. That is a fact,

Gee, I didn't realize you were there. I certainly didn't see you. Of course, it wasn't light yet.

because the full moon by itself gives only about -2 EV.

Nothing worse than pseudo-science as the basis for explanation. "The full moon by itself" is meaningless in the context of this photo (and many others). Why? Because the full moon is in a context that includes reflections from water (and other surfaces) and diffusion/diffraction/interference from clouds, fog, haze, dust, smoke, spray and humidity.

"The full moon by itself" means:

"the full moon by itself."

that it is the ultimate cause of all of the light in the scene.

There has to be some original source of light that causes these phenomena you list, none of which are light emitters or amplifiers. For instance, in a moonless and overcast night without ground artificial lighting or bioluminescence, even in an environment full of clouds, fog, haze, dust, smoke, spray and humidity and perfectly reflective surfaces, the scene would be totally dark.

And that is totally beside the point.  The presence of the moon--a very visible element in the image--was a given (one is tempted to say duh!).  The presence or absence of other factors has a huge effect on the amount of light available, and also the way that the available light illuminates surfaces, shadows, etc.  Anyone who has even limited powers of observation has noted that on some full-moon nights (with no fog or clouds) things are easier to see than on other full-moon nights.

Some of these threads seem to get derailed/hijacked into (pseudo) technical discussions that skirt, finesse, ignore and distort the original issue.  Sadly, this appears to be happening here.

Again, thanks to those who made positive contributions aimed at addressing the issue raised.

He is not doing "pseudo science".

Any scene with a light strength of 7EV on earth, without being full of strong artificial lights, must derive practically all of that 7EV from sunlight, and that's sunlight onto earth including the atmosphere.

How did you calculate 7EV for the illumination of the image?

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