What the imager has

Started 8 months ago | Discussions thread
mike earussi
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Re: What the imager has
In reply to Drplusplus, 8 months ago

Drplusplus wrote:

mike earussi wrote:

The problem is this: because only the blue layer can differentiate color variations for each set of 4 pixels, if you have the blue component the same but the other color channels different then instead of four different tones you're only going to see one that was the average of the four, so you're inevitably going to lose some subtle color variations that the present Merrill sensor can see.

I created this chart as an example of what I mean:

four unique colors get averaged into one if the blue channel is the same

Trying to understand your chart...why does B=R=G=100 give two different colors (dark gray and green)?

Did you perhaps mean to have G=200 on the green block and G=100 on the red block?

These are colors I created in PS to represent what would happen if four unique colors hit the Q sensor, but with the blue component the same in each. These channel combinations each create very different colors but would appear the same within that one quad block. The RGB numbers are just the PS color numbers. The Q block would create an average color the same size as the red and green blocks so the resulting color resolution would be the equivalent of a 4.9mp Foveon sensor, not a 19mp one.

So in some spots on the chip you'd have higher color resolution than in others, dependent entirely on whether the blue component was different for each pixel. It's going to be very interesting to see an actual comparison between the MerrillĀ and Q sensor, but it wouldn't surprise me at all to see the Merrill have higher resolution in some areas than the Quattro.

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