Comparing Olympus 4/3lenses to FX "Full Frame" offerings

Started Jan 25, 2014 | Discussions thread
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bobn2 Forum Pro • Posts: 41,403
Re: Wrong

Tiger1 wrote:

bobn2 wrote:

Tiger1 wrote:

What he states if “Thus each pixel of the output image from FF sensor represents four times the number of photons as that made from a FT sensor, assuming the same exposure (f-number, shutter speed and scene luminance)”

Stupefied down, If we view a FF image at 16mp output and compare it to FT image of equal output each pixel will contain 4 time more light information than the FT image

So he knows the photon capture efficiency of each photosite in aFF vs a FT sensor?

Funny you should say that:


Glad you're impressed.

Were did he get that information from?

The raw data from DxOmark, it needs some processiing to calculate the efficiency.

To know the output representation from the pixel you must know the capture efficiency of each photosite. Agree?

I think most manufacturers will try to get the efficiency of each 'photosite' in each of the Bayer submatrices the same, otherwise there will be a lot of pattern noise on the sensor.

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Well Bob thank you very much!!!!

The website info has confirmed to me what I was saying. Can you point out where the capture efficiency is always 4 times that of a FT sensor with a FF sensor?????

The capture efficiency is the same, by and large, so four times more area gets four times as many photons. I'm not sure what else you think is happening.

You can't and yes you are wrong with your own information!

Umm, no. You've got yourself very, very confused. My line is, and has been that pixel size does not greatly affect capture efficiency at all, and therefore the number of photons collected goes in proportion to sensor area, for the same light density.

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