Choosing between D4,D800,1DX,5D3

Started Oct 28, 2012 | Discussions thread
Zlik
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Re: Choosing between D4,D800,1DX,5D3
In reply to fft81, Oct 29, 2012

fft81 wrote:

rayman 2 wrote:

fft81 wrote:

rayman 2 wrote:

fft81 wrote:

I have d800 and i like it. One thing you should consider is your shooting style. Are you going to be free-handing or on tripod? Moving or stationary subjects? The thing is this: D800 has allot of pixels, hence very small angle camera move causes noticeable blur. With available light photography you are going to be limited to f/2.8 and slow shutter speeds. This means camera shake will be an issue if you are free handing. Also keep in mind that nikon 24-70 does not have VR. I'd almost suggest the 70-200 vr2 vs 24-70 for low light scenarios on d800 if you are free handing.

thats another myth !

The angle of the movement on the same lens IS the same.......!!!!

only if you print twice as large is thepixel per angle twice as large and therefore you need

to be more cautious !

BUT if you use a camera like the D4 over the D800 you are going to be able to use 1 stop higher iso

thats not a myth.... and you can use a speed that allows you to cut the blur in half with one stop...

The files from the D800 are more detailed though ! Even at higher iso... !

Peter

Basic math seems to contradict your logic. given 2 FX sensors behind the same lens focused on the same target the camera with higher resolution will have smaller area of the target fall into each pixel. Let's define some terms:

D-the distance from camera to target

S1 - width/height on the target covered by 1 pixel on sensor 1.

S2 - width/height on the target covered by 1 pixel on sensor 2.

if sensor 2 has higher pixel density say 36MPx vs 12MPx the area of each pixel is 3x smaller and width/height of each pixel is 1.7x smaller. So we have Tan(X1)/Tan(X2)=(S1/D)/(S2/D)=S1/S2=1.7 Where X1 and X2 are angles corresponding to 1 pixel for that focal length.

For small angles the small angle approximation holds true: Tan(x)=X where x is measured in radians. So this means 1.7=X1/X2. Remember, X1,X2 are angles measured in radians corresponding to 1 pixel. So what this all means is that you can tilt lower resolution camera an angle that is 1.7x larger than the angle you can tilt higher resolution camera before you blur adjacent pixels.

Lets say you are at 70mm and are 10 feet away. On 35mm sensor you get 34.3 degrees angle of view (diagonal), which equates to 19 degrees vertically. So each pixel on 36MPX sensor is equal 0.000704185 feet on the wall vertically. Now, if your image has fine detail, fine enough to tax such resolution, you will see blur on d800 with 0.0038 degree shift (pitch) of the camera.

For 12MPx sensor the 1-pixel blur does not start until 0.0065 degree pitch.

With constant hand shaking (constant from 1 body to the other) from 36mpx sensor to 12mpx sensor this translates to 1.7x longer exposure permitted on 12 mpx sensor than on 36mpx sensor with the same 1 pixel blur tolerance.

your angle does not change if you print both the same size and resolution...

If you print higher resolution on the D800 or print bigger with it then yes but given that both are the same no....... and thats how they should be compared....

At same size and same resolution they both are the same...

Peter

Problem is, you are thinking of total image angle on paper and not what happens inside the camera on the sensor. Ultimately you are right, the total view angle from 1FX body to the next will not change, however with the same angular displacement across both bodies the higher resolution one will have bury picture. But hey, you are right it's total angle will be the same.

If you magnify a 12MP 3 times to get 36MP, the picture will be blurry as well, duh.

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