At what KELVIN that each channel is equally amplified ?

Started Aug 7, 2012 | Discussions thread
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Re: Are you sure?
In reply to PhilPreston3072, Aug 9, 2012

Thanks for the info, Phil.

PhilPreston3072 wrote:

It would therefore seem that daylight is very close to where the channels are equal, perhaps just needing to shift the Kelvin slightly to the negative side for perfect equalness.

But I want to restate my original question.

In the daylight environment for example,
the correct WB (when the white object is WHITE) is, say 5500 K.

And if we want to present the color of that white object is rather blueish,
we turn the temperature slider (in ACR) to , say 2500,
the channel Blue get amplified about twice ?
The noise will also get amplified by twice too ?

By how many stop the final image will getting worse (in the noise term, if it can be translated in stop) ?

Or in other words,
By turning the temperature slider in ACR,

the thing that actually happen is changing the ratio of the data, is that correct ?
for example, (this is just a guess number)

2000 K is : Red = x, Blue = 2x, Green = x ---> noise is amplified by twice or 1 stop worse.

5000 K is : Red = x, Blue = x, Green = x ---> no noise is amplified.

8000 K is : Red = 2x Blue = x, Green = x ---> noise is amplified by twice or 1 stop worse.
(where x = original data)

In the illustration above,
the 5000 K is the answer of my original question in my OP.

Does anyone know what the exact number is ?
At what Kelvin, each channel is equally amplified ?

Many thanks,


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